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3 years ago

Find the area of the polygon below.

Mathematics

1 answer:

Rama09 [41]3 years ago

8 0

Answer:

assuming each square equals 1 the answer would be 29

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Rewrite using a single exponent.<br> 53.53

Helga [31]

Answer:

${5}^{6} \: \: or \: \: {25}^{3} = 15625$

Step-by-step explanation:

${5}^{3} \times {5}^{3}$

Here we can solve this in 2 ways ,

Method 1 :

${5}^{3} \times {5}^{3}$

Here the bases are equal. So,

$= > {5}^{3 + 3} = {5}^{6} = 15625$

Method 2 :

${5}^{3} \times {5}^{3}$

Here the exponents are same. So,

$= > {(5 \times 5)}^{3} = {25}^{3} = 15625$

4 0

2 years ago

22 less than the quotient of an unknown number and 35 is -25.

Agata [3.3K]

-22+(x/35)=-25
add 22 to both sides
x/35=-3
multiply both sides by 35 to cleaf raction
x=-105

number was -105

6 0

3 years ago

A right triangle has an area of 98 inches. If the triangle is an isosceles triangle, what are the lengths of the legs of the tri

Anna007 [38]

Answer:49

Step-by-step explanation:

A=ab/2

98=ab/2

98/2=ab

49=ab

5 0

2 years ago

Y = -1/5x + 3 ; (2,8)

Bad White [126]

8=-1/5(2)+3
8=-2/5+3
8=2 3/5
The equation is incorrect

6 0

3 years ago

You have $5600. The best interest rate you can find is 3%

EleoNora [17]

Answer:

18 years

Step-by-step explanation:

The formula for computing accrued amount A for a principal of P at an interest rate of r(in decimal) compounded n times in a year for t years is given by

$A = P(1 + \frac{r}{n})^{nt}$

Note that r is percentage converted to decimal. So 3% = 3/100 = 0.03

We can rearrange the above equation to:

$\frac{A}{P} = (1 + \frac{r}{n})^{nt}$

Taking logs on both sides

$log(\frac{A}{P}) = log(1 + \frac{r}{n})^{nt}$

This gives

$log(\frac{A}{P}) =nt \times log(1 + \frac{r}{n})\\So,\\nt = \frac{log(\frac{A}{P})}{ log(1 + \frac{r}{n})}$

In this particular problem, n = 4, , A= 9600, P = 5600, r =0.03, so r/n = 0.03/4 = 0.0075

1 + r/n = 1+0.0075 = 1.0075

4t = log(9600/5600)/log(1.0075) = log(1.714) / log(1.0075) = 0.234 /0.00325 = 72

t = 72/4 = 18 years

4 0

1 year ago