It is expected the height of the melted wax in this shape is 9.57 inches, this height would make the volume remain constant.
<h3>What is the volume of the spherical ball?</h3>
The volume of a sphere can be calculated using the formula V = 4/3 πr³. Let's use this formula to calculate the volume of the spherical ball of wax:
- V = 4/3 π8³
- V = 4/3 π 512
- V= 4/3 x 3.1416 x 512
- V =2144.66 cubic inches
<h3>What is the height of the new shape?</h3>
Considering the volume should be the same (2144.66 cubic inches) and the volume of this shape can be calculated by multiplying the sides, this would be the equation:
- 2144.66 = 14 x 16 x y ( unknown value)
- y= 2144.66 / 14 x 16
- y = 9.57
This means the height would be 9.57 inches.
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Answer:
140°
Step-by-step explanation:
Supplementary angles sum to 180° , thus
angle = 180° - 40° = 140° ← other angle
The function that describes the graph is an exponential function
<h3>How to determine the function type?</h3>
From the graph, we have the following highlights:
- Initially, when x increases; y seem not to increase
- Then, x and y increase at the same time
- Finally, y increase and x seem not to increase
The above is the description of an exponential function
Hence, the function that describes the graph is an exponential function
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Answer: $106.8
Step-by-step explanation:
Given that the bond price is $100.75
With a 6% brokerage fee
Find the total cost to the nearest cent
First, we calculate the 6% brokerage fee= 6/100 × 100.75
= 0.06 x 100.75
= 6.045
Total cost therefore is the sum of brokerage fee and the cost of bond
= $6.045 + $100.75
= $106.795
To the nearest cent = $106.8
Each dimension has to be 1" or bigger, otherwise the cube won't fit. _________ WAIT ! The container doesn't have to be rectangular, and that opens up a lot more possibilities. The smallest possible rectangular container is a little tiny cardboard cube whose dimensions are all 1", just like the contents. But you could also keep it in a container shaped like a pyramid, a cylinder, an egg, etc. If the container is a sphere, then its radius has to be at least 0.866 inch.