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rusak2 [61]
3 years ago
11

Find the area of the polygon below.

Mathematics
1 answer:
Rama09 [41]3 years ago
8 0

Answer:

assuming each square equals 1 the answer would be 29

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Three distributions, labeled (a), (b), and (c), are represented below by their histograms. Each distribution is symmetrical and
Neporo4naja [7]

Answer:

order is

αb<αc<αa

Step-by-step explanation:

in a )

number 4 and number  12 are showing 3 bullets while number 7 and 9 showing 2 bullets hence

standard deviation for a=3-2=1

in b)

number 4 ,7,9 and number  12 are showing 2 bullets while number 3 and 13 showing 1 bullet hence

standard deviation for a=2-1=1

in c)

number 4 ,7,9 and number  12 are showing 2 bullets while number 5 and 11 showing 1 bullet hence

standard deviation for a=2-1=1

order isαb<αc<αa


6 0
3 years ago
A toy box has a volume of 1/3 cubic yard.What is the volume of the toy box
artcher [175]
1/2 and that will be your answer
3 0
3 years ago
2.8 in fractional notation
Tcecarenko [31]
.28 if 1 was 100,and .28 was 2.8, then we divide 100 by 100 same for 2.8
6 0
4 years ago
If ADAB<br> ACBA,<br> ZDAB = 35° and ZCBA = 8x + 3<br> A<br> D<br> x = [?]<br> X<br> C<br> B
bekas [8.4K]

Answer:

x=4

Step-by-step explanation:

We are given that the triangles are congruent.

Specifically, the order of the letters gives that the angles ∠DAB and ∠CBA are corresponding parts of the two congruent triangles.  Since corresponding parts of congruent triangles are themselves congruent, ∠DAB ≅ ∠CBA.  Thus, m∠DAB = m∠CBA.

Given the expressions for the two angles, we can substitute into the equation, and solve for the requested variable.

m\angle DAB=m\angle CBA\\(35)=(8x+3)\\(35)-3=(8x+3\!\!\!\!\!\!\!\!\!\!{--})-3 \!\!\!\!\!\!\!\!\!\! {--}\\32=8x\\\dfrac {32}{8}=\dfrac {8x\!\!\!\!\!\!\! {-}}{8\!\!\!\! {-}}\\4=x

6 0
3 years ago
Read 2 more answers
X = t4, y = ln(t) (a) eliminate the parameter to find a cartesian equation of the curve.
kicyunya [14]
I guess when you say you want a cartesian equation of the curve, you would have to express them in cartesian coordinates of x and y. Thus, you must get rid of the variable t. The solution is as follows:

x = t⁴
y = ln(t)

e^y = e^(lnt)
e^y = t

Substuting this to the first equation,
x = (e^y)⁴
<em>x = e^4y</em>

7 0
3 years ago
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