A painter is painting a wall with an area of 150 ft2. He decides to paint half of the wall and then take a break. After his brea k, he paints half of the remaining unpainted portion and then takes another break. If he continues to paint half of the remaining unpainted portion between breaks, approximately what portion of the original wall will be painted when he takes his fifth break? 112.50 ft2
145.31 ft2
147.66 ft2
290.63 ft2
2 answers:
The answer is 141.35 ft² Before the first break, it was painted: 150 ft² ÷ 2 = 75 ft² Now it's left: 150 ft² - 75 ft² = 75 <span>ft² Before the second break, it was painted: 75 </span>ft² ÷ 2 = 37.5 <span>ft² Now it's left: 75 </span>ft² - 37.5 ft² = 37.5 <span>ft² Before the third break, it was painted: 37.5 </span>ft² ÷ 2 = 18.75 <span>ft² </span><span>Now it's left: </span>37.5 ft² - 18.75 ft² = 18.75 <span>ft² </span> <span>Before the fourth break, it was painted: </span>18.75 ft² ÷ 2 = 9.375 <span>ft² </span><span>Now it's left: </span>18.75 ft² - 9.375 ft² = 9.375 <span>ft² </span> <span>Before the fourth break, it was painted: </span>9.375 ft² ÷ 2 = 4.6875 <span>ft² </span><span>Now it's left: </span>9.375 ft² - 4.6875 ft² = 4.6875 ft² Now, we will sum what he painted for now: 75 ft² + 37.5 ft² + 18.75 ft² + 9.375 ft² 4.6875 ft² = 141.3125 ft² ≈ 141.35 ft² When the painter takes his fifth break, there will be <span>141.35 ft² of the wall painted.</span>
The painter would have 145.3125 ft^2 painted after the fifth break.
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