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Butoxors [25]
2 years ago
14

Can somebody please help me with this question i attached the photo from khan academy.

Mathematics
2 answers:
NeX [460]2 years ago
7 0

Answer:

C = (12, 13)

Step-by-step explanation:

The centre of the rectangle is O.

Find the difference between the x and y-values of O and A:

O_x-A_x=\dfrac{21}{2}-9=\dfrac32

O_y-A_y=\dfrac{19}{2}-6=\dfrac72

Now add those difference to the coordinates of O to find C:

x value of C = O_x+\dfrac32=\dfrac{21}{2}+\dfrac32=\dfrac{24}{2}=12

y value of C = O_y+\dfrac72=\dfrac{19}{2}+\dfrac72=\dfrac{26}{2}=13

Therefore, the coordinates of C = (12, 13)

Svet_ta [14]2 years ago
7 0

Answer:

Step-by-step explanation:

In rectangle the diagonals bisect each other. So,O is the midpoint of AC

Midpoint = \left(\dfrac{x_{1}+x_{2}}{2},\dfrac{y_{1}+y_{2}}{2} \right)\\\\\\x_{1}=9 \ and \ y_{1}=6\\\\\left(\dfrac{9+x_{2}}{2},\dfrac{6+y_{2}}{2} \right) = \left (\dfrac{21}{2},\dfrac{19}{2} \right)

Compare the x- coordinates and y- coordinates

\dfrac{9+x_{2}}{2}=\dfrac{21}{2}  \ ; \  \dfrac{6+y_{2}}{2}=\dfrac{19}{2}\\\\\\9+x_{2}=\dfrac{21}{2}*2 \ ; \ 6 +y_{2}=\dfrac{19}{2}*2

9 + x₂ = 21         ;  6 +y₂ = 19

     x₂ = 21 -9     ;       y₂ = 19 - 6

     x₂ = 12         ;        y₂ = 13

C(12 ,13)

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