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geniusboy [140]
3 years ago
8

Tom has saved $128, and his goal is to save $500. how much more must he save? which equation best represents this situation?

Mathematics
2 answers:
Margaret [11]3 years ago
7 0
He gone have to save 372 more
Vladimir79 [104]3 years ago
4 0
He must save $372 more dollars; 500-128=x
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Plz correct me if i'm wrong thx
OLEGan [10]

Answer:

30 fish

Step-by-step explanation:

Each fish needs 1/3 liter of water.

This means that there can be 3 fish in 1 liter of water. There are 10 liters in all. Multiply 3 with 10

3 x 10 = 30

30 fish is your answer.

~

6 0
3 years ago
Read 2 more answers
The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given
slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

\tau = 2438.155\,yr

The particular solution of the differential equation is:

m(t) = 10\cdot e^{-\frac{t}{2438.155} }

d) The amount of radium after 300 years is:

m(300) \approx 8.842\,g

4 0
3 years ago
Read 2 more answers
What is the solution to the system of equations shown below?
goblinko [34]

Answer:

  b.  (2, 5, 3)

Step-by-step explanation:

Trying the offered choices seems the fastest way to find the answer. The second choice works in all equations, hence is the solution.

Another strategy you can use is to see if the equations are dependent. Here, it looks like adding twice the third equation to the other two eliminates at least the x- and y-variables. If that eliminates z, then there are infinite solutions. Instead, it gives the equation ...

  7z = 21

  z = 3 . . . . . divide by 7

This answer is consistent with choice B, confirming that answer and eliminating the other choices.

5 0
3 years ago
Read 2 more answers
Babcock and Marks (2010) reviewed survey data from 2003–2005 and obtained an average of μ = 14 hours per week spent studying by
Dmitry [639]

Answer:

We do not have enough evidence to accept H₀

Step-by-step explanation:

Normal Distribution

size sample  =  n = 64   (very small sample for evaluating population of 5  years

Standard deviation 4,8

1.- Test hypothesis

H₀             null hypothesis        ⇒               μ₀ = 14       and

Hₐ     alternative hypothesis   ⇒                μ₀ ≠ 14

2.- z(c)  we assume α = 0,05  as we are dealing with a two test tail we should  consider   α/2  = 0.025.

From z table we the z(c) value

z(c) = 1.96           and of course by symmetry   z(c) = -1.96

3.- We proceed to compute z(s)

z(s)  = [ (  μ -  μ₀ ) /( σ/√n) ]           ⇒    z(s)  = - (1.5)*√64/4.8

z(s)  = - 2.5

We compare z(s)  and z(c)

z(s) < z(c)     -2.5  < -1.96  meaning  z(s) is in the rejection zone

we reject H₀ .

From the start we indicate sample size as to small for the experiment nonetheless we found that we dont have enough evidence to accept H₀

6 0
3 years ago
gillian earns 7.50 and hour babysitting on the weekends last week she babysat for 2.2 hours on Saturday and 3.5hours on Sunday h
ivolga24 [154]
Gillian earned $42.75 total. On Saturday (2.2 hours * 7.50 per hour) she earned $16.50. On Sunday (3.5 hours * 7.50 per hour) she earned $26.25. $26.25 + $16.50 = $42.75.
6 0
3 years ago
Read 2 more answers
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