Answer:
Step-by-step explanation:
diameter = 8 cm
radius = 8/2 = 4 cm
Area of circle = πr²
= 3.14*4*4 = 50.24 cm²
Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5
final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5
so the final exams has the largest IQR
The answer to this question is c I think
First find a common denominator
1/16(2/2) = 2/32
9/32 - 2/32 = 7/32
7/32 is your answer
hope this helps
