A student made the following chart to prove that AB2 + BC2 = AC2. (SEE ATTACHMENT)

Mathematics

2 answers:

spin [16.1K]2 years ago

8 0

Answer:

<h2>The first step is the error.</h2>

Step-by-step explanation:

The first step is wrong.

It's completely wrong because in the first step the student's justification of the congruence doesn't make sense. Basically because angle BCA is not corresponding to angle BCD, the right equivalence would be between angle BCA and DCB.

So, the student is demonstrating wrong the triangles congruence, because he is establishing a congruence between angles that don't correspond, there are in different spots.

Therefore, the first step is the error.

QveST [7]2 years ago

6 0

"<span>Triangle ABC is similar to triangle ABD 3. Angle ABC = Angle BAD and Angle BAC = Angle ABD" is the one step among the following choices given in the question that has the error. The correct option among all the options that are given in the question is the third option or option "3". I hope the answer has helped you.</span>

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What is the slope of each side of the triangle? the sides are A(-2,4) B(-1,1) C(2,3)

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Answer:

The slopes of three sides of triangle are as follows:

AB = -3

BC = 2/3

AC = -1/4

Step-by-step explanation:

The slope is denoted by m and is calculated using the formula

$m = \frac{y_2-y_1}{x_2-x_1}$

The given vertices are:

A(-2,4) B(-1,1) C(2,3)

The sides will be:

AB, BC, AC

Let m1 be the slope of AB

Let m2 be the slope of BC

Let m3 be the slope of AC

Now

$Slope\ of\ AB = m_1 = \frac{1-4}{-1+2} = \frac{-3}{1} = -3\\Slope\ of\ BC = m_2 = \frac{3-1}{2+1} = \frac{2}{3}\\Slope\ of\ AC = m_2 = \frac{3-4}{2+2} = \frac{-1}{4} = -\frac{1}{4}$