For a known standard deviation, the confidence interval for sample size = n is

where
x = average
n = sample size

= stad. deviation
z = contant that reflects confidence interval
Let a = x
Let b =

From the given information,
a - b = 0.432 (1)
a + b = 0.52 (2)
Add (1) and (2): 2a = 0.952 => a = 0.476
Subtract (2) from (1): -2b = -0.088 => b = 0.044
Therefore, the confidence interval may be written as
(0.476 - 0.044, 0.476 + 0.044), or as
(0.476

0.044)
J= obtuse
K=right
L=acute
M=acute
26 is a part of the whole. the proportion should be set up:
(26/x) = (5/100) It's the overall enrollment that is being asked.
If you also need to solve: Cross multiply, 26(100) = 5x, 2600 = 5x, divide both sides by 5, 520 is the enrollment