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Pepsi [2]
3 years ago
13

Please help me with this!!!!

Mathematics
1 answer:
olga_2 [115]3 years ago
5 0
The answer would have to be A
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28

Step-by-step explanation:

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How do you this question? Please explain.
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Answer:

(C) 2√15

Step-by-step explanation:

Recognize that all the triangles are right triangles, so are similar to each other. In these similar triangles, the ratio of the short side to the long side is the same for all.

... CB/CA = CT/CB

... CB² = CA·CT = 10·6 = 60 . . . . . . . . . . multiply by CA·CB; substitute values

... CB = √60 = 2√15 . . . . . . . take the square root; simplify

_____

<em>Comment on this solution</em>

The altitude to the hypotenuse of a right triangle (CB in this case) divides the hypotenuse into lengths such that the altitude is their geometric mean. That is ...

... CB = √(AC·CT) . . . . as above

This is true for any right triangle — another fact of geometry to put in your list of geometry facts.

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3 years ago
WHO DOESN'T LOVE MAX POINTS. MAX POINT QUESTION<br> PLS ANSWER THIS TRIGONOMETRY QUESTION
mezya [45]

Answer:

Solution given:

opposite:9

adjacent: 12

\theta=?

Relationship between opposite and adjacent is given by tan angle

so

Tan \theta=\frac{opposite} {adjacent}=\frac{9}{12}

Tan \theta=\frac{3}{4}

\theta=Tan^{-1}\frac{3}{4}

\bold{\theta=36.8°}

#11.

hypotenuse[h]=11cm

opposite/perpendicular[P]=b cm

adjacent/base[b]=a cm

now

\theta=62°

Relationship between height and hypotenuse is given by Sin angle

:.

Sin 62°=\frac{opposite}{hypotenuse}=\frac{b}{11}

doing crisscrossed multiplication

b=Sin 62°*11

:.b=9.71 cm

a) At <u>9</u><u>.</u><u>7</u><u>1</u><u> </u>cm height does the ladder touch the building.

again

Relationship between base and hypotenuse is given by Cos angle

:.Cos 62°=\frac{base}{hypotenuse}=\frac{a}{11}

doing crisscrossed multiplication

a=Cos 62°×11

a=5.16cm

b) the distance between the foot of the ladder and the building is <u>5.16cm.</u>

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2 years ago
He measured the height of the box to be 7 in. Then, Stephan drew a line from the center of one of the hexagons to each of its ve
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He measured the height of the box to be 7 in. Then<span>, </span>Stephan drew a line from the center of one of the hexagons to each of its vertices and noticed that<span> all .</span>
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If you convert 7 1/11 to decimals it comes out to .09 there fore 5.89+7.09
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