Answer:
9. m(YZ) = 102°
10. m(JKL) = 192°
11. m<GHF = 75°
Step-by-step explanation:
9. First, find the value of x
4x + 3 = 3x + 15 (inscribed angle that are subtended by the same arc are equal based on the inscribed angle theorem)
Collect like terms
4x - 3x = -3 + 15
x = 12
4x + 3 = ½(m(YZ)) (inscribed angle of a circle = ½ the measure of the intercepted arc)
Plug in the value of x
4(12) + 3 = ½(m(YZ))
48 + 3 = ½(m(YZ))
51 = ½(m(YZ))
Multiply both sides by 2
51*2 = m(YZ)
102 = m(YZ)
m(YZ) = 102°
10. First, find the value of x.
7x + 5 + 6x + 6 = 180° (opposite angles in an inscribed quadrilateral are supplementary)
Add like terms
13x + 11 = 180
13x = 180 - 11
13x = 169
x = 169/13
x = 13
7x + 5 = ½(m(JKL)) (inscribed angle of a circle = ½ the measure of the intercepted arc)
Plug in the value of x
7(13) + 5 = ½(m(JKL))
96 = ½(m(JKL))
Multiply both sides by 2
2*96 = m(JKL)
m(JKL) = 192°
11. First, find x.
5x + 15 = ½(11x + 18) (inscribed angle of a circle = ½ the measure of the intercepted arc)
Multiply both sides by 2
2(5x + 15) = 11x + 18
10x + 30 = 11x + 18
Collect like terms
10x - 11x = -30 + 18
-x = -12
Divide both sides by -1
x = 12
m<GHF = 5x + 15
Plug in the value of x
m<GHF = 5(12) + 15
m<GHF = 60 + 15
m<GHF = 75°
Answer:
27.385 cm longer would we expect Mike's arm span to be than George's.
Step-by-step explanation:
We have to find how many centimeters longer would we expect Mike's arm span to be than George's using the equation:
y= 4.5x + 0.977 x
where y= arm span
and x= height
Given:
Mike's height=x = 175 cm
so Mike's arm span= y= 4.5 x + 0.977 x
= 4.5* (175) + 0.977* (175)
= 787.5 + 170.975
= 958.475 cm
George's height = x = 170 cm
so George's arm span= y= 4.5 x + 0.977 x
= 4.5* (170) + 0.977* (170)
= 765 + 166.09
= 931.09 cm
Mike's arm span longer than George's = Mike's arm span - George's arm span
= 958.475 - 931.09
= 27.385 cm.
Answer:
Area = L²-5L
Step-by-step explanation:
Area = length * width
Length = L
Width = L - 5
Area = L * (L-5) = L²-5L
Answer:
Step-by-step explanation:
