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3 years ago

Harriet used the work below to determine the percent equivalent to One-eighth.

Mathematics

2 answers:

Klio2033 [76]3 years ago

8 0

Hello!
The answer is Step 2.
Hopefully I helped. :)
Please mark me brainilest if you get the chance

Alika [10]3 years ago

3 0

Answer: Its B ''In Step 2, she divided 8 by 100 instead of 100 by 8, so she cannot multiply the numerator by the factor.''

Step-by-step explanation:

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General solution for cos(5x)-cos(2x)=0

Irina-Kira [14]

<span>Simplifying cos(5x) + cos(2x) = 0
(5x) cos * 5x + cos(2x) = 0
</span> 5cos * x + cos(2x) = 0 Multiply cos * x 5cosx + cos(2x) = 0
(2x) 5cosx + cos * 2x = 0
5cosx + 2cos * x = 0 Multiply cos * x 5cosx + 2cosx = 0 5cosx + 2cosx = 7cosx 7cosx = 0 Solving 7cosx = 0 Solving for variable 'c'. cosx = 0 Simplifying cosx = 0

Hope this helps!

In short your answer is 0

7 0

4 years ago

In the equation, C = 8n + 25, C represents amount of money raised and n represents the number of pledges. How many pledges are n

DENIUS [597]

Answer:

103 pledges

Step-by-step explanation:

The equation we have here is;

C = 8n + 25

Now we need to find n given that c is $850

simply substitute for the value of c in the question

850 = 8n + 25

850-25 = 8n

825 = 8n

n = 825/8

n = 103.125

But since a pledge cannot be fractional, we can say that n = 103

5 0

3 years ago

Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o

GREYUIT [131]

Answer:

And then we can conclude that the middle 75% values of her lap times are from a=126.835 to b=132.585

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Solution to the problem

Let X the random variable that represent the times of a population, and for this case we know the distribution for X is given by:

$X \sim N(129.71,2.5)$

Where $\mu=129.71$ and $\sigma=2.5$

Since we want the middle 75% values then on tha tails we need 1-0.75 =0.25 or 25% of the data and since the distribution is symmetric we need 12.5 % of the values on each tail.

For this part we want to find a value a and b, such that we satisfy this condition:

$P(X>b)=0.125$ (a)

$P(X$ (b)

We can use the z score formula in order to find the value a and b given by:

$z=\frac{x-\mu}{\sigma}$

As we can see on the figure attached the z value that satisfy the condition (b) with 0.125 of the area on the left and 0.875 of the area on the right it's z=-1.15. On this case P(Z<-1.15)=0.125 and P(z>-1.15)=0.875

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=-1.15$

And if we solve for a we got

$a=129.71 -1.15*2.5=126.835$

So the value of height that separates the bottom 12.5% of data from the top 87.5% is 126.835.

As we can see on the figure attached the z value that satisfy the condition (b) with 0.875 of the area on the left and 0.125 of the area on the right it's z=1.15. On this case P(Z<1.15)=0.875 and P(Z>1.15)=0.125

If we use condition (b) from previous we have this:

$P(X>b)=P(\frac{X-\mu}{\sigma}>\frac{b-\mu}{\sigma})=0.125$