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2 years ago

Help as soon as possible!

Mathematics

1 answer:

Vika [28.1K]2 years ago

6 0

Answer:

$(7 + x + a)(7 - x - a)$

Here you buddy hope it helps!

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The speed limit on a road in Canada is 70 kilometers per hour. What is this speed in miles per hour? Round your answer to the ne

Marina CMI [18]

Answer:

43 miles/hr

Step-by-step explanation:

Use a conversion factor from km to miles while keeping track of your units:

70 km/hr x 0.62 miles/km = 43 miles/hr

4 0

3 years ago

Use properties of equality to Solve 7+3x = 5x+13 for x

mario62 [17]

We basically have to cancel values on both sides until they are both on common ground.

7 + 3x = 5x + 13

-7 from both sides...

3x = 5x + 6

-5x from both sides...

-2x = 6

/-2 from both sides...

x = -3

Hope this helps!

8 0

3 years ago

Can someone do question 13 please

Artyom0805 [142]

Answer:

A = 4/7

B = 2/3

C = 2/5

Step-by-step explanation:

It's Easy.

8 0

3 years ago

Read 2 more answers

EASY MATH QUESTION <br><br> PLEASE HELP

Arturiano [62]

Answer:

Step-by-step explanation:

When you find the absolute value of -2, it is 2, since that is how far away from the point 0 on a line. When you divide 2 by 2, it equals 1.

7 0

3 years ago

Read 2 more answers

Assume that in a particular military exercise involving two units, Red and Blue, thereis a 60 % chance that the Red unit will su

Marysya12 [62]

Answer: a) There are 42% chances that both units will meet their objectives.

b) There are 88% chances that one or the other but not both of the units will be successful.

Step-by-step explanation:

Since we have given that

Probability that the Red unit will successfully meet its objectives = 60% = P(R)

Probability that Blue unit will successfully meet its objectives = 70% = P(B)

Probability that only Red unit will be successful = P(only Red) = 18%

As we know that

$P(only\ red)=P(R)-P(R\cap B)\\\\0.18=0.60-P(R\cap B)\\\\0.18-0.60=-P(R\cap B)\\\\-0.42=-P(R\cap B)\\\\P(R\cap B)=42\%$

Hence, there are 42% chances that both units will meet their objectives.

the probability that one or the other but not both of the units will be successful is given by

$P(R\cup B)=P(R)+P(B)-P(R\cap B)\\\\P(R\cup B)=0.60+0.70-0.42\\\\P(R\cup B)=0.88\\\\P(R\cup B)=88\%$

Hence, there are 88% chances that one or the other but not both of the units will be successful.

6 0

3 years ago