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lesya692 [45]
3 years ago
7

IM CONFUSED PLEASE HELP! THANK YOU!

Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0

Answer:

Hope This Help If Not Sorry

Step-by-step explanation:

minimum  In mathematical analysis, the maxima and minima of a function, known collectively as extrema, are the largest and smallest value of the function, either within a given range, or on the entire domain.

aliina [53]3 years ago
3 0

9514 1404 393

Answer:

  (3,-5)

Step-by-step explanation:

The lowest point on the graph is (3,-5). That is the minimum.

The graph extends upward beyond the edge of the graph, so appears to have no maximum.

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Answer:

9.847 %

Step-by-step explanation:

Be p1 the probability that the mammogram detect breast cancer in a woman.

p1=81%.

The probability 'P' that independent and consecutive 'n' singular events with p probability occur is:

P=p_{1} ^{n}

In this case:

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3 years ago
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Step-by-step explanation:

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3 years ago
How can subtracting the equations help you solve the system?
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System of equations subtraction method

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3 years ago
Read 2 more answers
"Suppose an object falling in the atmosphere has mass m=15kg and the drag coefficient is γ=9kg/s. Recall that the differential e
Art [367]

Answer:

a. v(t)= -6.78e^{-16.33t} + 16.33 b. 16.33 m/s

Step-by-step explanation:

The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=e^{\int\limits^  {}k \, dt } =e^{kt}. We now multiply both sides of the equation by the integrating factor.

μv' + μkv = μg ⇒ e^{kt}v' + ke^{kt}v = ge^{kt} ⇒ [ve^{kt}]' = ge^{kt}. Integrating, we have

∫ [ve^{kt}]' = ∫ge^{kt}

    ve^{kt} = \frac{g}{k}e^{kt} + c

    v(t)=   \frac{g}{k} + ce^{-kt}.

From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have

9.55 = 9.8 × 15/9 + ce^{-16.33 * 0} = 16.33 + c

       c = 9.55 -16.33 = -6.78.

So, v(t)=   16.33 - 6.78e^{-16.33t}. m/s = - 6.78e^{-16.33t} + 16.33 m/s

b. Velocity of object at time t = 0.5

At t = 0.5, v = - 6.78e^{-16.33 x 0.5} + 16.33 m/s = 16.328 m/s ≅ 16.33 m/s

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