Answer:
20,600
Step-by-step explanation:
So, lets start this off by explaining what standard multiplication algorithms(Will call them SMA in this explanation) are.
In a standard multiplication algorithms, you multiply each digit on the bottom by the total digits on the top.
For example, in 21x23, we would multiply the 3 in the ones digit of the bottom number, by 21:
21x3 = 63
After this, we keep what we had in the ones place, however we "store" the 6 in the tens place above the 2 in 21. This is because we will add this to what we get when we multiply the tens place in the next step.
We would multiply the 2 in the tens digit of the bottom number, by the 21:
21x2 = 42
Then we add the 6 we stored from the first step:
42+6 = 48
Now we combine the first part of our answer by the second part of our answer.
What I mean by this is we got 48 in our second part of our answer, and 3 in our first part. We merge the 48 and the 3 to get 483:
48 and 3=483
Now lets work through your problem!
x25
824
So we start by multiplying the ones digit in the bottom(4), by the 25:
25x4=100
Since we got 100, we can put a zero in the ones place, and store the 1 in the hundreds digit in our math problem:
1
x25
824
====
0
Now we multiply the 25 by the 2 in the tens digit:
25*2 = 50
We now put a 0 in the tens digit, and we store the 5 with the 1 we already had:
6
x25
824
====
00
Now we multiply the 25 by the 8:
25*8=200
Then we add what we had in our storage:
200+6=206
Now we combine the third part of our answer(206) with the second(o) and third(0)
206 and 0 and 0 = 20600
So our answer is 20,600
Hope this helps!
