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Ganezh [65]
3 years ago
8

Simplify 6 to the negative 3rd power over 6 to the 5th. 68 6−2 1 over 6 to the 8th power 1 over 6 to the 2nd power

Mathematics
2 answers:
erik [133]3 years ago
8 0
\frac{ 6^{-3}}{ 6^{5} } =  6^{-3 -5} =  6^{-8}

\frac{ 6^{8} }{ 6^{2} } =   6^{8-2} =  6^{6}
Diano4ka-milaya [45]3 years ago
8 0

Answer:

The correct option is C) 1 over 6 to the 8th power.

Step-by-step explanation:

Consider the provided expression.

6 to the negative 3rd power over 6 to the 5th. This can be written as:

\frac{6^{-3}}{6^5}

Apply the exponent rule: \frac{x^a}{x^b}=\frac{1}{x^{b-a}}

By using the above rule.

\frac{1}{6^{5-(-3)}}

\frac{1}{6^{5+3}}

\frac{1}{6^{8}}

Hence, the simplified form is \frac{1}{6^{8}}

Thus, the correct option is C) 1 over 6 to the 8th power.

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yanalaym [24]

Answer:

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Step-by-step explanation:

To solve all of these questions you just need to scale. While scaling you can divide or multiply.

1. \frac{180 km}{4 hrs} (divide by 4 to get unit rate)

     unit rate = \frac{45km}{1hr}

2. If it takes one hour to travel 40 miles, then we don't have to scale or anything. We know \frac{40 miles}{1 hr}, the answer is...

"It'll only take one hour to travel 40 miles. This is correct because the unit rate is \frac{40 miles}{1 hr}. "

3. Knowing that the constant speed of the plane is \frac{800 km}{1 hour\\}, we can scale then add half of the unit rate to get our answer.

\frac{800 km}{1 hour\\} x 3 = \frac{2400 km}{3 hrs}   800 x 3 = 2400

then add half of unit rate which is \frac{400 km}{30 mins}  \sqrt[2]{800} = 400

so, our answer is \frac{2800 km}{3.5 hours}

4.  \frac{3km}{30 mins} <--- ( divided by 2) \frac{6 km}{1 hr} ( multiplied x 2.5) ---> \frac{15 km}{2.5 hrs}

To get an easier way to find the answer, if possible you can scale back farther than the 1 hour mark.

Elmer would take 2 and a half hours to ride 15 km.

5. The boys speed is \frac{4 km}{1 hr}. All we need to do is divide by 2. \sqrt[2]{8} = 4

3 0
3 years ago
when directed to solve a quadratic equation by completing the square, Sam arrived at the equation (x-(5/2))^2= (13/4). which equ
Tasya [4]
We have the following expression:
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 Let's rewrite the given expression:
 x ^ 2 - 5x + 25/4 = (13/4)
 x ^ 2 - 5x + 25/4 - 13/4 = 0
 x ^ 2 - 5x + 12/4 = 0
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 Answer:
 
the original equation given to Sam could have been:
 
x ^ 2 - 5x + 3 = 0
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3 years ago
What does P(X4=2,X3=3,X2=3,X1=2)
Dmitriy789 [7]

Answer:

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Step-by-step explanation:

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3 years ago
Your friend, Susannah, manages a sandwich shop. She collects data on the number of turkey sandwiches sold per day for a week. Ex
ExtremeBDS [4]

Susannah's data are illustration of measure of central tendencies

<u>(a) The mean</u>

To calculate the mean, she needs to divide the total number of turkey sandwiches sold, by the number of days.

The total is:

\mathbf{Total = 73 +88+85+88+99+134+129}

\mathbf{Total = 696}

The number of days is:

\mathbf{Day = 7}

So, the mean is:

\mathbf{Mean =\frac{Total}{Days}}

\mathbf{Mean =\frac{696}{7}}

\mathbf{Mean =99.4}

Hence, the mean number of turkey sandwiches sold is 99.4

<u>(b) The median</u>

To calculate the median, she needs to arrange the data in ascending or descending order, then select the middle item.

In ascending order, we have: 73, 85, 88, 88, 99, 129, 134

The middle item is 88

So:

\mathbf{Median = 88}

Hence, the median number of turkey sandwiches sold is 88

<u>(c) The mode</u>

This is the data that occurs most.

From the dataset, 88 appears twice (more than others).

So:

\mathbf{Mode = 88}

Hence, the mode number of turkey sandwiches sold is 88

<u>(d) The range</u>

This is the difference between the highest and least data

From the dataset,

The highest is 134, and the least is 73

So:

\mathbf{Range =134 - 73}

\mathbf{Range =61}

Hence, the range of turkey sandwiches sold is 61

The measure that would be most helpful is the median, because it is not affected by outliers.

Read more about measures of central tendencies at:

brainly.com/question/5495004

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Can someone help me?
AveGali [126]
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