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Marina86 [1]
2 years ago
14

Line segment PQ, with endpoints graphed on a coordinate grid at P(2,-2) and Q(5,-2) is translated four units to the left and two

units up. What length of the transformed line segment?
Mathematics
1 answer:
Oxana [17]2 years ago
5 0

Answer: 3

Step-by-step explanation:

We know that since a translation is a rigid motion, and that rigid motions preserve distance, the length of the transformed segment is the same as the given line segment.

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Please help me. I can’t do it
Maslowich

Answer: A) -8

B) - 41

C) - 39

Step-by-step explanation:

6 0
3 years ago
.Write a division equation so that it has a solution of -2
Irina18 [472]
Let’s take a random number such as 10, for example as the divisor of the equation.
Let’s take the dividend, or numerator of the fraction be x.
The solution of the fraction would be -2.

x/10 = -2
Or, x= -2 x 10
Or, x= -20

Therefore, -20/10 = -2
Ans: The division equation would be -20/10 = -2.
4 0
3 years ago
Dante's Mom wants to build a fence around their yard. Here are the measurements of the yard. What are the measurements of the mi
timama [110]

Answer:

(a)The missing measurements are 9 feet and 16\frac{1}{4}$ feet.

(b)Therefore, the length of the fence is  97\frac{1}{2}$ feet

Step-by-step explanation:

The diagram of the yard is attached below.

(a)I have labeled the missing dimensions of the yard as x and y.

Therefore:

y+8\frac{1}{4}=17 \frac{1}{4}\\y=17 \frac{1}{4}-8\frac{1}{4}\\y=9$ feet

Similarly:

x+15\frac{1}{4}=31\frac{1}{2}\\x=31\frac{1}{2}-15\frac{1}{4}\\x=31-15+\frac{1}{2}-\frac{1}{4}\\x=16+\frac{1}{4}\\x=16\frac{1}{4}$ feet

The missing measurements are 9 feet and 16\frac{1}{4}$ feet.

(b)Length of the Fence

The fence is rectangular shaped with:

Length = 31\frac{1}{2}$ feet

Width = 17 \frac{1}{4}$ feet

Perimeter of a Rectangle = 2(L+W)

Therefore, the length of the fence

=2(31\frac{1}{2}+17 \frac{1}{4})\\=2(31+17+\frac{1}{2}+ \frac{1}{4})\\=2(48+ \frac{3}{4})\\=96+\frac{3}{2}\\=97\frac{1}{2}$ feet

8 0
4 years ago
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

6 0
3 years ago
Three fourths of college students use the Internet more than the library. Nine hundredths use the library more. How many times m
Leno4ka [110]
Division
4/3X 100/9 = 8 1/3
5 0
4 years ago
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