Question

What is the quotient ? StartFraction 7 Superscript negative 6 Over 7 squared EndFraction StartFraction 1 Over 7 Superscript 8 EndFraction StartFraction 1 Over 7 cubed EndFraction 73 78.

Answer 1

The quotient of the start fraction 7 superscript 7 negative 6 over 7 squared end fractions is,

$\dfrac{1}{7^8}$

What is the quotient?

Quotient is the resultant number which is obtained by dividing a number with another. Let a number a is divided by number b. Then the quotient of these two number will be,

$q=\dfrac{a}{b}$

Here, (a, b) are the real numbers.

The number given in the problem is,

$\dfrac{7^{-6}}{7^2}$

Let the quotient of these number is n. Therefore,

$n=\dfrac{7^{-6}}{7^2}$

Now if the power of numerator is negative, then it can be written in denominator with positive power of the same number. Therefore, the above equation written as,

$n=\dfrac{1}{7^2\times7^{6}}\\n=\dfrac{1}{7^{2+6}}\\n=\dfrac{1}{7^8}$

Hence, the quotient of the start fraction 7 superscript 7 negative 6 over 7 squared end fractions is,

$\dfrac{1}{7^8}$

Learn more about the quotient here;

brainly.com/question/673545

Answer 2

Answer:

It would be A. $\frac{1}{7^{8} }$.

Step-by-step explanation:

Hope this helps!