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Svet_ta [14]
3 years ago
5

John is driving around town. When he reaches the gas station, he notes that he has traveled 20 miles. He reaches home 2 hours la

ter and notes that he has traveled 30 miles.
If d represents the distance and t represents the time, in hours, John has traveled since the gas station, which of the following equations can be used to model this situation?
Mathematics
1 answer:
Troyanec [42]3 years ago
8 0

Answer:

d=5t+20

Step-by-step explanation:

The equation that will model this situation will be of the form

d=mt+b

where t is the time in hours john has traveled since the gas station, and  d is the distance.

Now we know that John has already traveled 20 miles when he is at the gas station, this means at t=0, d=20; or

20=m(0)+b

\boxed{b=20}

Thus we have

d=mt+20.

Now we need to figure out m.

When John reaches home 2 hours later he notes that he has traveled 30 miles, which means he has traveled 30 - 20 = 10 miles; thus we have

m= \frac{\Delta d}{\Delta t} =\frac{10 miles}{2hours} =5

\boxed{m=5}

Now we have the full equation:

\boxed{d=5t+20}

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-2/3X + 4/3 = -10/3 <br><br>solve each equation by first eliminating all fractions ​
bagirrra123 [75]

The solution of -2/3X + 4/3 = -10/3 by first eliminating all fractions is 7.0006

<u>Solution:</u>

We have been given an equation as follows:

-\frac{2}{3 x}+\frac{4}{3}=-\frac{10}{3}

And we have been asked to solve each equation by first eliminating all fractions.

The only way to solve this equation is by converting each of its components into decimals since it is stated in the question that we should not solve it in fraction form.

To do so we will individually convert the fractions to decimals and then substitute them back into the equation.

The 1st fraction in decimal form is:

-\frac{2}{3}=-0.6666

The 2nd fraction in decimal form is:

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And the 3rd fraction in decimal form is:

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So, now we substitute the decimals instead of the fractions in the given equation as follows:

\begin{array}{l}{-0.6666 x+1.3333=-3.3333} \\\\ {-0.6666 x=-3.3333-1.3333} \\\\ {x=-\frac{4.6666}{-0.6666}} \\\\ {x=7.0006}\end{array}

Therefore, the value of x in decimal from is 7.0006

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