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2 years ago

Line K has the equation 9x-4y=-5x4.

Mathematics

1 answer:

Wewaii [24]2 years ago

3 0

<h3>Answer: y = (9/4)x - 2</h3>

=======================================================

Explanation:

Line K is 9x-4y=-5*4 which is the same as 9x-4y=-20

Rule: Anything parallel to Ax+By = C is of the form Ax+By = D.

The equation 9x-4y=-20 has A = 9, B = -4 and C = -20.

That means Ax+By = D becomes 9x-4y = D.

------------------------------

Plug in the coordinates (x,y) = (4,7) and compute the value of D.

9x-4y = D

D = 9x-4y

D = 9(4)-4(7)

D = 36 - 28

D = 8

So 9x-4y = D becomes 9x-4y = 8

----------------------------

The last step is to solve for y to get the equation in y = mx+b form.

9x-4y = 8

-4y = 8-9x

-4y = -9x+8

y = (-9x+8)/(-4)

y = (-9x)/(-4) + 8/(-4)

y = (9/4)x - 2 is the slope-intercept form of line L

The equation is in y = mx+b form where,

m = 9/4 = slope

b = -2 = y intercept

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Answer:

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Step-by-step explanation:

Step 1: Write equation

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Step 2: Solve for x

Add 4x to both sides: 2x + 1 = 9
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Plug in x to verify it's a solution.

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Answer:

Therefore his average speed for the entire trip is 8 mph.

Step-by-step explanation:

Given, In 50 minutes Luis traveled uphill to gift store at 6 mph.

6 mph means in 1 h= 60 minutes Luis can covered 6 mile.

In 1 minutes Luis can covered $\frac{6}{60}$ mile.

In 50 minutes Luis can covered $\frac{6\times 50}{60}$ mile

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Again when he come back at home, the speed was 12 mph.

12 mph means in 1 h= 60 minutes Luis can covered 12 mile.

Therefore he traveled 12 mile in 60 minutes

He traveled 1 mile in $\frac{60}{12}$ minutes.

He traveled 5 mile in $\frac{60\times 5}{12}$ minutes

= 25 minutes.

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$\textrm{Average speed}=\frac{\textrm{Total distance}}{\Textrm {total time}}$

$=\frac{10}{75}$ m/min

$=\frac{10\times 60}{75}$ mph

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Therefore his average speed for the entire trip is 8 mph.

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3 years ago

How do I solve this

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Answer:

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Step-by-step explanation:

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Which expression will simplify to 1?

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Let us check each Option :

$\mathsf{First\;Option : \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m + 9}{m - 9}\right)}$

$\mathsf{\implies \left(\dfrac{m + 9}{m - 9}\right)^2\;\neq\;1}$

$\mathsf{Second\;Option : \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m - 9}{m + 9}\right)}$

$\mathsf{\implies 1}$

$\mathsf{Third\;Option : \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{9 + m}{9 - m}\right)}$

$\mathsf{\implies \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m + 9}{-(m - 9)}\right)}$

$\mathsf{\implies-\left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m + 9}{m - 9}\right)}$

$\mathsf{\implies-\left(\dfrac{m + 9}{m - 9}\right)^2\;\neq\;1}$

$\mathsf{Fourth\;Option : \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{9 - m}{9 + m}\right)}$

$\mathsf{\implies \left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{-(m - 9)}{9 + m}\right)}$

$\mathsf{\implies -\left(\dfrac{m + 9}{m - 9}\right)\left(\dfrac{m - 9}{9 + m}\right)}$

$\mathsf{\implies -1\;\neq\;1}$

Answer : Option (2)

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