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Marina86 [1]
2 years ago
10

Elena has $5 for pencils. Each pencil costs $0.30. How many pencils can she buy? *No run-on decimals please!*

Mathematics
2 answers:
aleksley [76]2 years ago
7 0

Answer:

she could by 16 pencils with 20 cents left over

Step-by-step explanation:

so the fraction is 16 and 2/3

so she could buy 16 pencils and have 20 cents leftover

just olya [345]2 years ago
7 0

Answer:

She can buy 16 pencils

Step-by-step explanation:

You would not be able to write this as a run on decimal because she is buying pencils and you cant but part of a pencil

.30 x 16= 4.8  so you would not be able to buy anymore than 16

You could always buy less and she would have 20 cents left over if she bough 16.

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Artyom0805 [142]
First multiply -3 to -5/3. Giving you -14=5+b. Then subtract 5 from both sides to isolate b. -14+5= -9 so b=-9 which is your y-intercept
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3 years ago
What is the common ratio for the geometric sequence? 32, 8, 2, 12, ... Enter your answer in the box.
mamaluj [8]

Answer:

Given sequence is not a geometric progression and there will be no common ration for this sequence.

Step-by-step explanation:

Need to determine common ration for the following geometric sequence

32, 8, 2, 12, ...

In given geometric sequence  

a1 = 32, a2=8, a3=2, a4=12 ……….

Common ratio = \frac{a_2}{a_1} =\frac{a_3}{a_2} =\frac{a_4}{a_3}

\frac{a_2}{a_1}=\frac{8}{32}=\frac{1}{4}

\frac{a_3}{a_2} =\frac{2}{8}=\frac{1}{4}

\frac{a_4}{a_3}=\frac{12}{2}=6

Since \frac{a_2}{a_1}=\frac{a_3}{a_2}\neq\frac{a_4}{a_3}  so we can say that given sequence is not a geometric progression and there will no no common ration for this sequence.

3 0
3 years ago
Three consecutive even integers whose sum is -48​
Salsk061 [2.6K]
Three consecutive even integers whose sum is -48
6 0
3 years ago
Help with this .........
Umnica [9.8K]

9514 1404 393

Answer:

  x = 30

Step-by-step explanation:

Supplementary angles total 180°.

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