Twelve and eight hundred seventy three thousandths
Step-by-step explanation:
For quadratic equation ax^2 + bx + c = 0 to have two distinct real roots,
b^2 - 4ac must be positive.
b^2 - 4ac > 0
(k - 3)^2 - 4(3 - 2k) > 0
k^2 - 6k + 9 - 12 + 8k > 0
k^2 + 2k - 3 > 0
Answer:
given x+1 > 10,
x > 10 - 1
x > 9
which means x MUST BE more than 9 , which also means 9 isnt included in the inequality therefore x = 9 is not a solution.
We have that
x²<span> + 7x + c
</span><span>Group
terms that contain the same variable
</span>(x² + 7x )+ c
<span>Complete
the square. Remember to balance the equation
</span>(x² + 7x+3.5² )+ c-3.5²
Rewrite as perfect squares
(x+3.5)²+ c-3.5²
so
c-3.5² must be zero
c-3.5²=0------- c=3.5²------> c=12.25
the answer isthe value of c must be 12.25
Answer:
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Step-by-step explanation:
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