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3 years ago

Hey can somebody help me

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

6 0

Answer:

x^2/3

Step-by-step explanation:

Exponent properties!

x^4*x^9 for example,

we add the exponents because the base of the exponents is the same.

now back to the question

x^4/3 * x^2/3

we add those exponents!

6/3 or 2

so we have( x^2)^1/3

^2 and ^1/3 multiply!

we have x^2/3

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What is −13+2z=−56 Thanks

Zinaida [17]

<h3>Original Equation:</h3>

$-\frac{1}{3}+2z=-\frac{5}{6}$

<h3>Steps:</h3>

<em>*To solve for a variable, isolate the desired variable onto one side.</em>

Firstly, we want to add 1/3 to each side however -5/6 and 1/3 do not share the same denominator, and we want them to have that and we can do that by finding the LCD, or lowest common denominator. To find the LCD, list the multiples of 6 and 3 and the lowest multiple that they share is their LCD. In this case, their LCD is 6. Multiply -1/3 by 2/2:

$-\frac{1}{3}\times \frac{2}{2}=-\frac{2}{6}\\\\-\frac{2}{6}+2z=-\frac{5}{6}$

Now that we have common denominators, add both sides by 2/6:

$2z=-\frac{3}{6}\\\\2z=-\frac{1}{2}$

Next, you want to cancel out 2 to isolate z. Usually, one would divide both sides by 2, however remember that <u>dividing by a number is the same as multiplying by it's reciprocal.</u> To find a number's reciprocal, flip the numerator and denominator around. In this case, since 2 is a <em>whole number</em> this means that the denominator is 1. In this case: 2/1 would become 1/2. Multiply both sides by 1/2:

$\frac{1}{2}\times 2z= -\frac{1}{2}\times \frac{1}{2}\\\\z=-\frac{1}{4}$

<h3>Final Answer:</h3>

<u>Your final answer is z = -1/4.</u>

7 0

3 years ago

Mark is adding X and -4. He finds the LCD to be 3x. What should he do next to find the sum?

MariettaO [177]

Answer:

Step-by-step explanation:

8 0

3 years ago

Simplify the imaginary number sqr -75

m_a_m_a [10]

Answer:

5i $\sqrt{3}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

and $\sqrt{-1}$ = i

Given

$\sqrt{-75}$

= $\sqrt{25(3)(-1)}$

= $\sqrt{25}$ × $\sqrt{3}$ × $\sqrt{-1}$

= 5 × $\sqrt{3}$ × i

= 5i $\sqrt{3}$

3 0

3 years ago

How are rational functions similar to linear, quadratic, or exponential functions? How are they different? When are these simila

jeyben [28]

Answer:

See explanation below for further details.

Step-by-step explanation:

A rational consist of two real numbers such that:

$\frac{a}{b} =c$

If c is a polynomial with a certain grade, then, both the numerator and the denominator must be also polynomials and the grade of the numerator must be greater than denominator.

If c is linear function, that is, a first order polynomial, then a must be a (n+1)-th polynomial and b must be a n-th polynomial.

Example:

If $a = x^{2}$ and $b = x$ , then:

$c = \frac{x^{2}}{x}$

$c = x$

If c is a quadratic function, that is, a second order polynomial, then a must be a (n+1)-th polynomial and b must be a n-th polynomial.

Example

If $a = 3\cdot x^{3}$ and $b = x$ , then:

$c = \frac{3\cdot x^{3}}{x}$

$c = 3\cdot x^{2}$

But if c is an exponential, both the numerator and the denominator must be therefore exponential function and grade of each exponential function must different to the other.

Example

If $a = 10^{2x}$ and $b = 3\cdot 10^x$ , then: