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1 year ago

0.3(4+8)/-0.1+5/(9.2+13.2) HELP ME PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

aleksklad [387]1 year ago

8 0

0.3(4+8)/-0.1+5/(9.2+13.2)= -35.7767857143

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I know the answer to number 7 but I just want to see if you guys know it

elixir [45]

Plugging 10 for k in the expression gives us
$2(10)^2+5(10)+1$ We simplify this expression to $200+50+1=251$
251 is your answer

4 0

3 years ago

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a normally distributed data set has a mean of 35 and a standard deviation of 2.5 what z-score corresponds to a data value of 32

Oksanka [162]

$z=\dfrac{32-35}{2.5}=-1.2$

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3 years ago

Find the number that makes the ratio equivalent to 1:6.<br> 9:__

Anarel [89]

Answer: 54

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Explanation:

The first ratio is 1:6. The jump from 1 to 6 has us multiplying the 1 by 6 to get 6.
1*6 = 6
So we follow the same rule of "multiply by 6" to go from 9 to 54 (9*6 = 54)

Or you can use a proportion to get
1/6 = 9/x
1*x = 6*9 ... cross multiply
x = 54
and we get the same answer

6 0

2 years ago

How many liters of 60% alcohol solution should be added to 40 liters of a 20% alcohol solution to make a 50% solution?

kolbaska11 [484]

Answer:

120 liters of 60% alcohol solution is needed

Step-by-step explanation:

Let's assume

x liters of 60% alcohol solution is added

so, we get solution as

$=\frac{60}{100}\times x$

$=0.6x$

we are given

40 liters of a 20% alcohol solution is

$=40\times\frac{20}{100}$

$=8$

so, total alcohol solution is

$=8+0.6x$

now, we can find total solutions

total solutions is

$=x+40$

now, it is making 50% solution

so, we get

$\frac{8+0.6x}{x+40} =\frac{50}{100}$

now, we can solve for x

$\left(8+0.6x\right)\cdot \:100=\left(x+40\right)\cdot \:50$

$800+60x=50x+2000$

$10x=1200$

$x=120$

So,

120 liters of 60% alcohol solution is needed

4 0

2 years ago

Tyler went to the supermarket to buy food for a food pantry. He has $36, and can carry up to 20 pounds of food in his backpack.

horrorfan [7]

Answer:

solutions: (2, 10), (4, 5)
non-solutions: all other points

Step-by-step explanation:

It can be useful to graph the inequalities related to Tyler's limits of money and weight.

1x +3y ≤ 36 . . . . . . the limit on the cost of the items Tyler can afford

1x +1.5y ≤ 20 . . . . . the limit on the weight of the items Tyler can carry

Then plotting the given points shows that only (2, 10) and (4, 5) are in the doubly-shaded area that is the solution space. The other points are not a solution.

6 0

2 years ago