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djverab [1.8K]
2 years ago
15

A tank is filled with 20 litres of water. Half the water is removed and replaced with anti freece and thoroughly mixed. Half thi

s mixture is then removed and replaced with anti-freeze This process continues. find the first five terms in the sequence of amounts of water in the tank at each stage​
Mathematics
1 answer:
mr Goodwill [35]2 years ago
7 0

Answer:

The sequence of amountof water is geometric(first term

20, commonratio

0.5) but the se-quence of antifreezeis not (a geometricsequence cannot havezero as its first termsince that would implythat all terms are zero).

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Hep I’m trash at math
puteri [66]

Step-by-step explanation:

\pi {r}^{2}  \frac{h}{3}

π×4×4×8/3

π×16×8/3

128/3×π

128/3π cm²

5 0
2 years ago
Read 2 more answers
There are 9,481 eligible voters in a precinct. 500 were selected at random and asked to indicate whether they planned to vote fo
maria [59]

Answer:

The confidence limits for the proportion that plan to vote for the Democratic incumbent are 0.725 and 0.775.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Of the 500 surveyed, 350 said they were going to vote for the Democratic incumbent.

This means that n = 500, \pi = \frac{350}{500} = 0.75

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 - 1.28\sqrt{\frac{0.75*0.25}{500}} = 0.725

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 + 1.28\sqrt{\frac{0.75*0.25}{500}} = 0.775

The confidence limits for the proportion that plan to vote for the Democratic incumbent are 0.725 and 0.775.

8 0
3 years ago
The LCM of 2 numbers is 60 and 1 of the numbers is 7 less than the other number. What are the numbers?
Phoenix [80]
Let's represent the two numbers by x and y.  Then xy=60.  The smaller number here is x=y-7.

Then (y-7)y=60, or y^2 - 7y - 60 = 0.  Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:

discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191.  Because the discriminant is positive, this equation has two real, unequal roots, which are
        -(-7) + sqrt(191)
y = -------------------------
             -2(1)

and 

        -(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
             -2(1)

Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.


Try thinking this way:  If the LCM is 60, then xy = 60.  What would happen if x=5 and y=12?  Is xy = 60?  Yes.  Is 5 seven less than 12?  Yes.






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3 years ago
A. Determine the y-intercept by<br> substituting 0 for x
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What’s the question?
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which of the following equations represents a linear function? A. y=3X^2 B. Y=2- 6/x C. y= x +6 D.y=1/2x+3
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<span> C. y= x +6 is the linear equation</span>
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