What is the third quartile of this data set 20,21,24,25,28,29,35,37,39,42,44
dezoksy [38]
Answer:
The third quartile would be <u>39</u>.
Step-by-step explanation:
• Since the numbers are already in order, the next step would be to find the median:
- The <u>median</u> is the middle number; found by ordering all data points and picking out the one in the middle.
• The <u>first quartile</u>, is denoted as Q1 and is the middle number that falls between the smallest value of the data set and the median.
- The first quartile would be 24.
• The <u>third quartile</u>, is denoted as Q3 and is the median of the upper half of the data set.
- The third quartile would be 39.
If I helped, please mark me the Brainliest!?!
Answer:
yeah so you just do that
Step-by-step explanation:
Answer:
13x-2
Step-by-step explanation:
1) distribute the negative sign to each term in the second parentheses
(7x-10)-(-6x-8)
7x-10+6x+8
2) combine like terms
7x+6x= 13x
-10+8=-2
13x-2
Hope this helps!
If we were to foil
after experieence
we know
ax²+bx+c=0
and
in form
(ax+b)(cx+d)=0
if we expand it, we get
acx²+bcx+adx+bd=0
or
(ac)x²+(bc+ad)x+(bd)=0
compare to
ax²+bx+c=0
we notice that the middle terms (x terms) are
b=(bc+ad)
so
in form
(2x-1)(1x+5)
b=bc+ad=(-1*1+2*5)=-1+10=9
b=9
or you could just expand it
8.5≤
