Let the distance between the earth and the sun be denoted as 'z'.
From the trigonometric rules:
tan(theta)=opposite/adjacent
In this case: theta=x , opposite=y and adjacent=z
tan(x)=y/z
All terms in the equation are known except for 'z'.
therefore the distance between the earth and the sun denoted by the symbol 'z' is equal to: y/tanx
ANSWER:
E[X] ≈ m ln m
STEP-BY-STEP EXPLANATION:
Hint: Let X be the number needed. It is useful to represent X by
m
X = ∑ Xi
i=1
where each Xi is a geometric random variable
Solution: Assume that there is a sufficiently large number of coupons such that removing a finite number of them does not change the probability that a coupon of a given type is draw. Let X be the number of coupons picked
m
X = ∑ Xi
i=1
where Xi is the number of coupons picked between drawing the (i − 1)th coupon type and drawing i th coupon type. It should be clear that X1 = 1. Also, for each i:
Xi ∼ geometric
P r{Xi = n} =
Such a random variable has expectation:
E [Xi
] =
= 
Next we use the fact that the expectation of a sum is the sum of the expectation, thus:
m m m m
E[X] = E ∑ Xi = ∑ E Xi = ∑
= m ∑
= mHm
i=1 i=1 i=1 i=1
In the case of large m this takes on the limit:
E[X] ≈ m ln m
Answer:
C
Y=-2/3+1
Step-by-step explanation:
It would be negative because that is where Y is 0
A! You need to multiply all the numbers together
Answer:
srry this aint no 5 point question Ma'am (absolutely no hardfeelings :D)
Step-by-step explanation: