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Firlakuza [10]
3 years ago
11

Juan Hernandez, a Cuban athlete who visits the United States and Europe frequently, is allowed to return with a limited number o

f consumer items not generally available in Cuba. The items, which are carried in a duffel bag, cannot exceed a weight of 5 pounds. Once Juan is in Cuba, he sells the items at highly inflated prices. The three most popular items in Cuba are denim jeans, CD players, and CDs of U.S. rock groups. The weight and profit (in U.S. dollars) of each item are as follows:
Item Weight (lb.) Profit
Denim jeans 2.1 $40
CD players 3.2 48
Compact discs 0.8 16
uan wants to determine the combination of items he should pack in his duffel bag to maximize his profit. This problem is an example of a type of integer programming problem known as a "knapsack" problem. Formulate and solve the problem.
Mathematics
1 answer:
Svet_ta [14]3 years ago
8 0

Answer:

z (max) = 96

x₁  = 2

x₂ = 0

x₃ = 1

Step-by-step explanation:

Fromproblem statement:

                                    weight (lb) .          Profit $

Denim jeans                    2.1                         40

CD players                       3.2                        48

Compact Discs                0.8                        16

Objective Function z is:

z = 40*x₁  + 48*x₂ + 16*x₃             to maximize

Subject to:

Weight constrain:    5 lb

2.1*x₁  +   3.2*x₂   + 0.8*x₃

x₁≥ 0   x₂  ≥ 0        x₃ ≥ 0      All integers

Using AtomZmath on-line solver and after 2 iterations

Solution:

z (max) = 96

x₁  = 2

x₂ = 0

x₃ = 1

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Null hypothesis:p_{1} = p_{2}    

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z=\frac{0.410-0.350}{\sqrt{0.382(1-0.382)(\frac{1}{1000}+\frac{1}{900})}}=2.688    

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Step-by-step explanation:

Data given and notation    

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n_{1}=1000 sample 1 selected  

n_{2}=900 sample 2 selected  

p_{1}=\frac{410}{1000}=0.410 represent the proportion estimated of people indicating that their financial security was more than fair in 2012

p_{2}=\frac{315}{900}=0.350 represent the proportion estimated of people indicating that their financial security was more than fair in 2010  

\hat p represent the pooled estimate of p

z would represent the statistic (variable of interest)    

p_v represent the value for the test (variable of interest)  

\alpha=0.05 significance level given  

Part a: Concepts and formulas to use    

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

Hypothesis testing

We need to apply a z test to compare proportions, and the statistic is given by:    

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{410+315}{1000+900}=0.382  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.    

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:    

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Statistical decision  

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Comparing the p value with the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to to reject the null hypothesis, and we can say that the proportions analyzed are significantly different at 5% of significance.

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