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3 years ago

A point at (28, −50) is reflected over the y-axis.

Mathematics

2 answers:

KonstantinChe [14]3 years ago

8 0

Answer:

(-28, -50)

Step-by-step explanation:

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is taken to be the additive inverse. The reflection of point (x, y) across the y-axis is (-x, y).

Basically when you reflect something over the y axis , the y coordinate stays the same, the x coordinate becomes the opposite of what it was.

kifflom [539]3 years ago

6 0

Answer:

The Answer is (-28, -50)

Step-by-step explanation:

I took the test (k12)

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Rewrite the expression as a product of two factors 4x + 8

Veseljchak [2.6K]

You would get 2 (2x+4). The two factors are the 2, and the (2x+4)

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3 years ago

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In a two-digit number the units digit is three less than the tens digit. If the digits are reversed, the sum of the reversed num

makvit [3.9K]

Answer:

74.

Step-by-step explanation:

Let the number be xy.

Then from the given data

x = y + 3..........(1)

The numerical value of xy is 10x + y so the second equation is

10x + y + 10y + x = 121

11x + 11y = 121 Simplifying:

x + y = 11

x = -y + 11 .........(2) Adding equations (1) and (2):

2x = 14

x = 7

and therefore y = 7 - 3 = 4.

7 0

4 years ago

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10/7=x/5 which of the following equation can be used to solve for the value of X?

V125BC [204]

Answer:

10*5 = 7x

Step-by-step explanation:

We can solve using cross products

10*5 = 7x

50 = 7x

divide each side by 7

50/7 =7x/7

50/7 =x

5 0

3 years ago

Given the following information about a hypothesis test of the difference between two means based on independent random samples,

HACTEHA [7]

Answer:

$S^2_p =\frac{(13-1)(5)^2 +(10 -1)(3)^2}{13 +10 -2}=18.143$

And the deviation would be just the square root of the variance:

$S_p=4.259$

Then the statistic is given by:

$t=\frac{(12 -9)-(0)}{4.259\sqrt{\frac{1}{13}+\frac{1}{10}}}=1.674$

And the correct option would be:

t = 1.674

Step-by-step explanation:

Data given:

$n_1 =13$ represent the sample size for group 1

$n_2 =10$ represent the sample size for group 2

$\bar X_1 =12$ represent the sample mean for the group 1

$\bar X_2 =9$ represent the sample mean for the group 2

$s_1=5$ represent the sample standard deviation for group 1

$s_2=3$ represent the sample standard deviation for group 2

We are assuming two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The pooled variance is given by:

$S^2_p =\frac{(13-1)(5)^2 +(10 -1)(3)^2}{13 +10 -2}=18.143$

And the deviation would be just the square root of the variance:

$S_p=4.259$

Then the statistic is given by:

$t=\frac{(12 -9)-(0)}{4.259\sqrt{\frac{1}{13}+\frac{1}{10}}}=1.674$

And the correct option would be:

t = 1.674

4 0

4 years ago

PLS HELP ASAP calculate the distance between the two points. (18, -24) & (87, 100)

GarryVolchara [31]

Answer:

<h3>The answer is 141.90 units</h3>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(18, -24) & (87, 100)

The distance between them is

$d = \sqrt{ ({18 - 87})^{2} + ({ - 24 - 100})^{2} } \\ = \sqrt{ ( { - 69})^{2} + ( { - 124})^{2} } \\ = \sqrt{4761 + 15376} \\ = \sqrt{20137} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = 141.90489773...$

We have the final answer as

<h3>141.90 units</h3>

Hope this helps you

5 0

3 years ago