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3 years ago

PLS HELP ASAP calculate the distance between the two points. (18, -24) & (87, 100)

Mathematics

1 answer:

GarryVolchara [31]3 years ago

5 0

Answer:

<h3>The answer is 141.90 units</h3>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(18, -24) & (87, 100)

The distance between them is

$d = \sqrt{ ({18 - 87})^{2} + ({ - 24 - 100})^{2} } \\ = \sqrt{ ( { - 69})^{2} + ( { - 124})^{2} } \\ = \sqrt{4761 + 15376} \\ = \sqrt{20137} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = 141.90489773...$

We have the final answer as

<h3>141.90 units</h3>

Hope this helps you

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A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha

White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

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Here p(t)= the coefficient of B =-r

The integrating factor $=e^{\int p(t) dt$

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Multiplying the integrating factor the both sides of equation (1)

$e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}$

$\Rightarrow e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt$

Integrating both sides

$\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt$

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$\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}$

Initial condition B=7864 when t =0

$\therefore 7864= \frac{k}{r} - Ce^0$

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Then the general solution is

$B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}$

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

$B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}$

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D is the right answer because g is midpoint of ah and e is midpoint of ab and eg is parallel to bh so eg equals half bh

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