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Anika [276]
2 years ago
9

A gas that has a volume of 28 liters, a temperature of 450c, and an unknown pressure has its volume increased to 34 liters and i

ts temperature decreased to 350c. If i measure the pressure after the change to be 2. 0 atm, what was the original pressure of the gas?.
SAT
1 answer:
sp2606 [1]2 years ago
4 0

Answer:

2.82 atm

Explanation:

Initial:

V1 = 28 liters, T1 = 450 C = 450 + 273 K = 723 K, P1 = ?

Final:

V2 = 34 liters, T2 = 350 C = 350 + 273 K = 623 K, P2 = 2.0 atm

Use P1 * V1 / T1 = P2 * V2 / T2

so P1 = P2 * (V2/V1) * (T1/T2) = 2.0 * (34/28) * (723/623) = 2.82 atm

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Answer:

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Explanation:

Entropy is defined as the measure of possible arrangement of the atoms or molecules. Entropy change for the the freezing process mole of 1 liquid methanol at -97.6 degree celcius and 1 atm will be -18.07 J/mol.

The entropy change can be calculated by the given formula:

 

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llustrated above is an urban heat-island profile. What is the source of the majority of the heat downtown?
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