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2 years ago

100 grams of iron ore contains 30.06% oxygen find the empirical formula

Chemistry

1 answer:

Serga [27]2 years ago

8 0

Answer: Fe2O3

Explanation:

100 grams of iron ore = 30.06% oxygen

100 - 30.06 = 69.94% iron

Mr of Iron = 55.85

Mr of Oxygen = 16

Iron = 69.94/55.85 = 1.252

Oxygen = 30.06/16 = 1.879

1.879 / 1.252 = 1.5 of Oxygen

1.252/1.252 = 1 of Iron

we can write that as Fe1O1.5 but we can't use decimals therefore we have to multiply the whole thing by 2

So it comes out to be Fe2O3

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Given the two half-reactions, what must be done in the next step before the reaction can be balanced? Au3+ --> Au I- --> I

Artyom0805 [142]

Answer:

The balance equation is

$2Au^{+3} + 6I^{-}$ → $2Au + 3I_{2}$

Explanation:

first, we have to make sure that the atoms are balanced

$Au^{+3}$ → $Au^{}$

$2I^{-}$ → $I_{2}$

then we proceed to balance charges of each half-reaction

$Au^{+3} + 3e^{-}$ → $Au^{}$

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Now we multiply the half-reactions to match the number of electrons in each one

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4 years ago

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A solution is prepared by mixing 2.17 g of an unknown non-electrolyte with 225.0 g of chloroform. The freezing point of the resu

Deffense [45]

Answer:

The molar mass of the unknown non-electrolyte is 64.3 g/mol

Explanation:

Step 1: Data given

Mass of an unknown non-electrolyte = 2.17 grams

Mass of chloroform = 225.0 grams

The freezing point of the resulting solution is –64.2 °C

The freezing point of pure chloroform is – 63.5°C

kf = 4.68°C/m

Step 2: Calculate molality

ΔT = i*kf*m

⇒ ΔT = The freezing point depression = T (pure solvent) − T(solution) = -63.5°C + 64.2 °C = 0.7 °C

⇒i = the van't Hoff factor = non-electrolyte = 1

⇒ kf = the freezing point depression constant = 4.68 °C/m

⇒ m = molality = moles unknown non-electrolyte / mass chloroform

0.7 °C = 1 * 4.68 °C/m * m

m = 0.150 molal

Step 3: Calculate moles unknown non-electrolyte

molality = moles unknown non-electrolyte / mass chloroform

Moles unknown non-electrolyte = 0.150 molal * 0.225 kg

Moles unknown non-electrolyte = 0.03375 moles

Step 4: Calculate molecular mass unknown non-electrolyte

Molar mass = mass / moles

Molar mass = 2.17 grams / 0.03375 moles

Molar mass = 64.3 g/mol

The molar mass of the unknown non-electrolyte is 64.3 g/mol

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100 grams of iron ore contains 30.06% oxygen find the empirical formula​

100 grams of iron ore contains 30.06% oxygen find the empirical formula