All categories

2 years ago

100 grams of iron ore contains 30.06% oxygen find the empirical formula

Chemistry

1 answer:

Serga [27]2 years ago

8 0

Answer: Fe2O3

Explanation:

100 grams of iron ore = 30.06% oxygen

100 - 30.06 = 69.94% iron

Mr of Iron = 55.85

Mr of Oxygen = 16

Iron = 69.94/55.85 = 1.252

Oxygen = 30.06/16 = 1.879

1.879 / 1.252 = 1.5 of Oxygen

1.252/1.252 = 1 of Iron

we can write that as Fe1O1.5 but we can't use decimals therefore we have to multiply the whole thing by 2

So it comes out to be Fe2O3

You might be interested in

The mobile electrons of a pure metal are called what

olchik [2.2K]

Answer:

This means that the metal is more properly viewed as an array of positive ions surrounded by a “sea of mobile valence electrons.” Electrons which are capable of moving freely throughout the empty orbitals of the metallic crystal are called delocalized electrons (Figure below).

5 0

3 years ago

What is something that has mass and takes up space

Leni [432]

Humans.
Humans have mass and take up space. :)

Hope this helps!

5 0

3 years ago

Read 2 more answers

Stu Dent has finished his titration, and he comes to you for help with the calculations. He tells you that 20.00 mL of unknown c

Alexus [3.1K]

Answer:

0.3229 M HBr(aq)

0.08436M H₂SO₄(aq)

Explanation:

Stu Dent has finished his titration, and he comes to you for help with the calculations. He tells you that 20.00 mL of unknown concentration HBr(aq) required 18.45 mL of 0.3500 M NaOH(aq) to neutralize it, to the point where thymol blue indicator changed from pale yellow to very pale blue. Calculate the concentration (molarity) of Stu's HBr(aq) sample.

Let's consider the balanced equation for the reaction between HBr(aq) and NaOH(aq).

NaOH(aq) + HBr(aq) ⇄ NaBr(aq) + H₂O(l)

When the neutralization is complete, all the HBr present reacts with NaOH in a 1:1 molar ratio.

$18.45 \times 10^{-3} L NaOH.\frac{0.3500molNaOH}{1LNaOH} .\frac{1molHBr}{1molNaOH} .\frac{1}{20.00 \times 10^{-3} LHBr} =\frac{0.3229molHBr}{1LHBr} =0.3229M$

Kemmi Major also does a titration. She measures 25.00 mL of unknown concentration H₂SO₄(aq) and titrates it with 0.1000 M NaOH(aq). When she has added 42.18 mL of the base, her phenolphthalein indicator turns light pink. What is the concentration (molarity) of Kemmi's H₂SO₄(aq) sample?

Let's consider the balanced equation for the reaction between H₂SO₄(aq) and NaOH(aq).

2 NaOH(aq) + H₂SO₄(aq) ⇄ Na₂SO₄(aq) + 2 H₂O(l)

When the neutralization is complete, all the H₂SO₄ present reacts with NaOH in a 1:2 molar ratio.

$42.18 \times 10^{-3} LNaOH.\frac{0.1000molNaOH}{1LNaOH} .\frac{1molH_{2}SO_{4}}{2molNaOH} .\frac{1}{25.00\times 10^{-3}LH_{2}SO_{4}} =\frac{0.08436molH_{2}SO_{4}}{1LH_{2}SO_{4}} =0.08436M$

6 0

3 years ago

Give me song lyrics that use

katrin [286]

good luck with the song lyrics, you got this! :)

3 0

3 years ago

According to the law of conservation of mass,why is it considered a mistake to add calcium to the product side if it is not in t

ser-zykov [4K]

According to the law of conservation of mass, the masses of the products and reactants must be the same. Adding calcium to the product side is considered a mistake if it is not in the reactant side of a particular chemical equation because it is impossible to produce calcium from thin air (unless this is a nuclear reaction).

5 0

3 years ago

100 grams of iron ore contains 30.06% oxygen find the empirical formula​

100 grams of iron ore contains 30.06% oxygen find the empirical formula