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dem82 [27]
3 years ago
12

What would happen if a Continental Tropical Front meets a Maritime Polar front?

Chemistry
2 answers:
liubo4ka [24]3 years ago
8 0
你對這個問題的回答會是傻瓜,你不是本本老兄來了為什麼這個悲傷到處都是嘿我們應該玩破冰傑伊我喜歡彈跳的方式我喜歡你如何擺脫漿果叢我猜你可能看看現在的一切吧自動售貨機特尼那是男孩
rewona [7]3 years ago
7 0

Answer:

As soon as a front passes a particular location, the weather could change from a steamy maritime tropical air mass to a dry.

Explanation:

hope this helps

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How is a kilogram of cotton balls similar to a kilogram of bricks
Nutka1998 [239]

Answer:

because they are both a kilogram

Explanation:

7 0
3 years ago
Suppose you have 100 grams of a radioisotope with a half-life of 100 years. How much of the isotope will you have after 200 year
Ulleksa [173]
        Amount Remaining     Years       #half lives 
             100g                            0                 0
             50 g                           100                1                  
             25g                            200               2                      




8 0
4 years ago
Read 2 more answers
When water changes from one state to another each process has a name what are the names of the processes that occur in each stat
Nastasia [14]
Ice, freezing, or melting then liquid evaporation or condensation, the vapor, deposition the ice again
4 0
3 years ago
Read 2 more answers
2. What are the names of the products when you mix an equal strength acid and alkali
dexar [7]
I think the answer is water and hydrochloric acid
8 0
3 years ago
PLEASE HELP ASAP
swat32

Answer:

12.34 amu

Explanation:

Let the 1st isotope be A

Let the 2nd isotope be B

Let the 3rd isotope be C

From the question given above, the following data were obtained:

1st Isotope (A):

Mass of A = 12.32 amu

Abundance (A%) = 19.5%

2nd isotope (B):

Mass of B = 13.08 amu

Abundance (B%) = 26.23%

3rd isotope (C):

Mass of C = 11.99 amu

Abundance (C%) = 54.27%

Atomic mass of X =?

The atomic mass of the element X can be obtained as follow:

Atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]

= [(12.32 × 19.5)/100] + [(13.08 × 26.23)/100] + [(11.99 × 54.27)/100]

= 2.402 + 3.431 + 6.507

= 12.34 amu

Thus, the atomic mass of the element X is 12.34 amu

7 0
3 years ago
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