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Talja [164]
3 years ago
9

Predict the effect of the E2delG mutation on the resulting FGF5-L protein. Justify your prediction. Researchers identify a diffe

rent mutation in the FGF5 gene that results in the overexpression of FGF5. Predict the most likely effect of this mutation on the ratio of hairs in growth phase to hairs in rest phase compared with the ratio when the normal FGF5 allele is expressed
Biology
1 answer:
Andre45 [30]3 years ago
5 0

The most likely effect of FGF5 mutation is an increase on the ratio of hairs in the growth phase to hairs in rest phase compared with the ratio when the normal FGF5 allele. It leads to trichomegaly.

<h3>What does FGF5 encode?</h3>

The FGF5 gene code for glycosaminoglycan binding proteins, which are commonly expressed in the root sheath of the hair follicle.

The maximum FGF5  gene expression occurs in the late anagen step (i.e., when the hair follicle forms a new hair shaft) of the hair cycle.

Mutations of this gene (FGF5) produce trichomegaly, thereby increasing the portion of hair in the anagen phase.

Learn more about the anagen phase here:

brainly.com/question/4556162

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pThe probability of having an offspring with both the dominant phenotypes for both genes is equal to the product of the individu
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The product probability rule states P(A∩B) = P(A) x P(B). In the exposed example, the probability of having a dominant phenotype is 9/16.

<h3>What is the product probability rule?</h3>

The product probability rule allows us to calculate the probability of occurrence of event A and event B at the same time.

It is about a joint probability of two or more events that might happen simultaneously, not excluding each other.

This rule is based on the dependence or independence of the events. If two events A and B are independent of each other, the occurrence of one of them does not affect the occurrence of the other one.

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P(A∩B) = P(A) x P(B)

The probability of inheriting one of the alleles from each parent is 0.5 (beacause each parent has two alleles).

According to this, the probability of having a dominant phenotype for both traits depends on the paretal genotypes.

For instance, let us analyze the cross between two dihybrid individuals AaBb  x  AaBb.

Assuming the involved genes code for different traits and both are independent genes, for easier calculations, we can perform crosses that involve each of the genes separately -events-, and then multiply de results according to the genotype and phenotype we are interested in (A-B-)

<u>Gene A</u>

Parentals) Aa   x   Aa

Gametes) A   a     A   a

Punnett square)       A(1/2)      a(1/2)

                    A(1/2)    AA(1/4)     Aa(1/4)

                    a(1/2)     Aa(1/4)      aa(1/4)

F1) Genotype

      <u>1/4 AA</u> ⇒ 1/2A x 1/2A

      2/4 = 1/2 Aa ⇒ (1/2A x 1/2a) + (1/2A x 1/2a)

      1/4 aa ⇒ 1/2a x 1/2a

      Phenotype

     <u> 3/4 A-</u> ⇒ 1/4AA + 2/4Aa

      1/2 aa

     

<u>Gene B</u>

Parentals) Bb   x   Bb

Gametes) B   b     B    b

Punnett square)   B      b

                   B       BB    Bb

                    b       Bb   bb

F1 Genotype

      <u>1/4 BB</u> ⇒ 1/2B x 1/2B

      2/4 = 1/2 Bb ⇒ (1/2B x 1/2b) + (1/2B x 1/2b)

      1/4 bb ⇒ 1/2b x 1/2b

      Phenotype

     <u> 3/4 B-</u> ⇒ 1/4 BB + 2/4 Bb

      1/2 bb

The probability of having a dominant genotype and phenotype for both traits is,

  • Genotpe AABB ⇒ 1/4 AA x 1/4 BB = <u>1/16 AABB</u>
  • Phenotype A-B- ⇒ 3/4 A-  x  3/4 B- = <u>9/16 A-B-</u>

<u />

<u />

You can learn more about the product probability rule in crosses at

brainly.com/question/13049972

brainly.com/question/14933381

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