The small number is 2.
The large number is 3.
<u>Step-by-step explanation:</u>
Let the two consecutive numbers be x and x+1.
- x be the small integer.
- x+1 be the large integer.
The sum of these two consecutive integers = small integer + large integer
The sum of these two consecutive integers is x+x+1 = (2x+1)
It is given that,
- The sum of two consecutive integers is one less than three times the smaller integer.
- This means that, (2x+1) is one less than three times the smaller integer.
- Here, the small integer is represented as x.
<u>Therefore, it can determined that :</u>
(2x+1) = 3x-1
Keeping x term on one side and constants on other side,
3x-2x = 1+1
x = 2
Therefore, the small number is 2 and the large number is x+1 = 3.
Answer:
The first 2 and the last one
Step-by-step explanation:
You need to have an input per output, and to choose one or multiple the need to have a continuous pattern. Ex.+5 ad -2 on both sides every time would be a linear function.
Answer:
Approximatley 5.8 units.
Step-by-step explanation:
We are given two angles, ∠S and ∠T, and the side opposite to ∠T. We need to find the unknown side opposite to ∠S. Therefore, we can use the Law of Sines. The Law of Sines states that:
Replacing them with the respective variables, we have:
Plug in what we know. 20° for ∠S, 17° for ∠T, and 5 for <em>t</em>. Ignore the third term:
Solve for <em>s</em>, the unknown side. Cross multiply:
