Problem 3: Let x = price of bag of pretzels Let y = price of box of granola bars
We have Lesley's purchase: 4x+2y=13.50
And Landon's: 1x+5y=17.55
We can use the elimination method. Let's negate Landon's purchase by multiplying by -1. -1x-5y=-17.55
We add this four times to Lesley's purchase to eliminate the x variable.
2y-20y=13.50-70.2
-18y=-56.7
y = $3.15 = Price of box of granola bars
Plug back into Landon's purchase to solve for pretzels.
x+5*3.15=17.55
x+15.75=17.55
x = $1.80 = price of bag of pretzels
Problem 4.
Let w = number of wood bats sold
Let m = number of metal bats sold
From sales information we have: w + m = 23
24w+30m=606
Substitution works well here. Solve for w in the first equation, w = 23 - m, and plug this into the second.
24*(23-m)+30m=606
552-24m+30m=606
6m=54
m=9 = number of metal bats sold
Therefore since w = 23-m, w = 23-9 = 14. 14 wooden bats were sold.
That’s the answer with steps
The height of the blue spruce was 45.
We find the mean by adding all of the data points and dividing by the number of data points. We will add the unknown value x and change the number we're dividing by to 7:
(160+320+100+110+200+220+x)/7 = 165
(1110+x)/7 = 165
Multiply both sides by 7:
1110 + x = 1155
Subtract 1110 from both sides:
x = 45
Answer:
X >>>>> Y
–1 >>>> 16
0 >>>>> 8
1 >>>>> 4
2 >>>>> 2
3 >>>>> 1
Step-by-step explanation:
From the question given above,
y = 8 × (½)ˣ
When x = –1, y =?
y = 8 × (½)ˣ
y = 8 × (½)¯¹
y = 8 × 2
y = 16
When x = 1, y =?
y = 8 × (½)ˣ
y = 8 × (½)¹
y = 8 × ½
y = 4
When x = 2, y =?
y = 8 × (½)ˣ
y = 8 × (½)²
y = 8 × ¼
y = 2
When x = 3, y =?
y = 8 × (½)ˣ
y = 8 × (½)³
y = 8 × ⅛
y = 1
SUMMARY:
X >>>>> Y
–1 >>>> 16
0 >>>>> 8
1 >>>>> 4
2 >>>>> 2
3 >>>>> 1
Answer:
<u><em>Answer is below</em></u>
Step-by-step explanation:
<em><u>-2 ×^2 - 4y +6</u></em>
<em><u>Evaluate simply means to form an idea of something</u></em>
<em><u>So Evaluate for x=−3,y=−2</u></em>
<em><u>−2(−3)2−(4)(−2)+6</u></em>
<em><u>−2(−3)2−(4)(−2)+6</u></em>
<em><u>Answer =−4</u></em>
