4+48=52
if you divide 52 by 4 you should get 13.
this means michael paid 13 dollars per pizza :)
The key is to do it on ur own
If AC = CD, then each is half of AD, so each has length 12/2 = 6.
If AB = BC, then each is half of AC, so each has length 6/2 = 3.
The lengths are:
... AB = 3
... AC = 6
... AD = 12
... BC = 3
... BD = 9
... CD = 6
Since we have just listed the lengths of "all segments in the diagram," we presume that is the list from which our random segment is chosen. Of these 6 segments listed, 4 are longer than 3. The probability of interest is ...
... 4/6 = 2/3
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If you consider the segments in the diagram to be only AB, BC, and CD, then your probability is 1/3, since only CD is longer than 3.
The general approach to this is to write the (x, y) coordinates of the trajectory's peak in terms of the sine and cosine of the launch angle α. Then use a trig identity (sin(2α)² + cos(2α)² = 1) to eliminate the dependence on α.
You should get
t = v₀sin(α)/g
x = v₀²sin(2α)/(2g)
y = v₀²(1-cos(2α))/(4g)
Solve each of the latter two equations for the trig function, then substitute those expressions into the trig identity above. Divide by the coefficient of x² and rearrange to get the expression shown.
