Can someone help me on these to questions ???
1 answer:
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The Great Pyramids of Khufu is located in El Giza, Egypt. Pyramids were built to serve as tombs for the pharaohs of ancient Egypt. The Great Pyramid is 481 feet high and has a square base with a base edge length of 756 feet. What is the approximate surface area (to the nearest hundredth) of the pyramid.
(HINT: Is the base on the surface?)
Square with edge length = 756 feet
Square= 1/2 × 297.45 × 481
= 286,146.9ft
= 1,037,709,9ft. base with edge length =756 feet
area of square,
= Side² = 756 × 756 = 571,563ft²
⇒ area of base = 1/2 = 756/2 = 378ft
By pythagorean theorem,
H² = P²+B²
(481)² = P²+(378)²
P² = (481)²-(378)²
P² = 231,361-142,884
P² = 88,477
P = √88,477
P = 297.45
Area of triangle =1/2 × b × h
= 1/2x297.45*481
= 148.725×481
= 71,536.725
Now 4 area of triangle = 4×71,536.725
= 286,146.9ft
total surface area of pyramid + square
= 751,563+286,146.
= 1,037,709,9ft.
First one
when doing the quadratic equation, we come across something called the determinant
when this is positive, we have 2 real roots
when this is 0, we have 1 real root
whenthis is negative, we have 2 imaginary rots
we want 2imaginary roots so
<0
we have
1x^2-6x+c=0
a=1
b=-6
c=c
<0
<0
square root both sies
36-4c<0
add 4c both sides
36<4c
divide both sides by 4
9<c
c>9
D is the answer (not b or c)
remember
√-1=i
a²-b²=(a-b)(a+b)
we want to do
x^2-(-9)
now we have to take the sqrt of -9
√-9=(√-1)(√9)=(i)(3)=3i
(x)^3-(3i)^2
(x-3i)(x+3i)
B is answer
when doing the quadratic equation, we come across something called the determinant
when this is positive, we have 2 real roots
when this is 0, we have 1 real root
whenthis is negative, we have 2 imaginary rots
we want 2imaginary roots so
we have
1x^2-6x+c=0
a=1
b=-6
c=c
square root both sies
36-4c<0
add 4c both sides
36<4c
divide both sides by 4
9<c
c>9
D is the answer (not b or c)
remember
√-1=i
a²-b²=(a-b)(a+b)
we want to do
x^2-(-9)
now we have to take the sqrt of -9
√-9=(√-1)(√9)=(i)(3)=3i
(x)^3-(3i)^2
(x-3i)(x+3i)
B is answer