The total number of pennies on row 1 is: 1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 =.

A subway train starts from rest at a station and accelerates at a rate of 1. 60m/s2 for 14. 0 s. It runs at constant speed for 7

MariettaO [177]

Please what’s your question

7 0

3 years ago

Trey has answered 15 E-mails. This is 20% of E-mails he must answer. How many E-mails does he need to answer? Pls help hkhxdfsrw

RSB [31]

ANSWER:

75 emails.

Trey has to answer a total of 75 emails.

STEP-BY-STEP EXPLANATION:

If:

20% of emails = 15

Then:

20% × 5 = 15 × 5

100% of emails = 75

3 0

3 years ago

Read 2 more answers

Imagine that the mayor of your town receives most of his reelection find them from cattle industry clients as soon as he is elec

const2013 [10]

Answer:

interesting

Explanation:

5 0

3 years ago

What is the term for a preset command in a spreadsheet?

Murljashka [212]

The terminology for a preset command that is used in a spreadsheet is a: function.

<h3>What is a spreadsheet?</h3>

A spreadsheet refers to a to a document which comprises cells that are arranged in a tabulated format with rows and columns. Also, a spreadsheet is typically used in various field to do the following on a data:

Sort

Calculate

Format

Arrange

<h3>What is a function?</h3>

In Computer technology, a function refers to a named portion of a block of executable code that can be used as a preset command to perform a specific task, which is usually a single, related action.

In this context, we can infer and logically deduce that a function is the terminology for a preset command that is used in a spreadsheet.

Read more on spreadsheets here: brainly.com/question/4965119

#SPJ1

3 0

2 years ago

a 15.0 kg block is attached to a very light horizontal spring of force constant 575 n/m and is resting on a smooth horizontal ta

Luden [163]

The instantaneous velocity of the 15 kg. mass just after collision can be found by the principle of linear momentum.

a) The speed of the 15 kg. just after collision is 2 m/s.

b) The type of collision is inelastic collision

c) The compression of the spring is approximately 0.323 m.

Reasons:

The given parameters are;

Mass of the block attached to the spring, m₁ = 15.0 kg

Force constant of the spring, K = 575 N/m

Mass of the stone that strikes the block, m₂ = 3.00 kg

Speed of the stone, v₂ = 8.00 m/s

Speed with which the stone rebounds, v₃ = 2.00 m/s

a) The total initial momentum = 3 kg. × 8 m/s = 24 kg·m/s

The final momentum, just after collision = 3 × (-2) kg·m/s + 15 kg ×v₁

By conservation of momentum, we have;

24 kg·m/s = 3 × (-2) kg·m/s + 15 kg ×v₁

$v_1 = \dfrac{24 \, kg \cdot m/s + 6 \, kg \cdot m/s}{15 \, kg} = 2 \, m/s$

The speed of the 15 kg. just after collision, v₁ = 2 m/s.

b) A collision is elastic when the kinetic energy of the collision is conserved

The initial kinetic energy, K.E.₁ = 0.5 × 3 kg. ×(8 m/s)² = 96 J

The sum of the final kinetic energy are;

0.5 × 3 kg. × (2 m/s)² + 0.5 × 15 kg × (2 m/s)² = 36 J

The initial kinetic energy ≠ The final kinetic energy

Therefore, the collision is not elastic

(c) The kinetic energy given by the block = The elastic potential energy gained by the spring

Kinetic energy of the block, K.E. = 0.5 × 15 kg × (2 m/s)² = 30 J

Elastic energy gained by the block = 0.5 × K × x² = 0.5 × 575 N/m × x²

Therefore;

0.5 × 575 N/m × x² = 30 J

$x^2 = \dfrac{30 \, J}{0.5 \times 575 \, N/m} = \dfrac{12}{115} \, m^2$

$x = 2 \cdot \sqrt{\dfrac{3}{115} } \approx 0.323$

The compression of the spring, x ≈ 0.323 m.

Learn more here:

brainly.com/question/7694106

Questions;

(a) The speed of the 15 kg mass immediately after the collision.

(b) Determine the type of collision; Elastic or inelastic collision.

(c) The distance to which the spring is compressed by the block.

3 0

3 years ago