The Gibbs free energy ΔG for the vaporisation of 2-methylbutane, in KJ/mol is 8.24 KJ/mol
<h3>Data obtained from the question </h3>
- Enthalpy change (ΔH) = 25. 22 KJ/mol
- Change in entropy (ΔS) = 84.48 J/Kmol = 84.48 / 1000 = 8.448×10¯² KJ/Kmol
- Temperature (T) = 201 K
- Gibbs free energy (ΔG) =?
<h3>How to determine the Gibbs free energy </h3>
The Gibbs free energy for the reaction can be obtained as follow:
ΔG = ΔH – TΔS
ΔG = 25.22 – (201 × 8.448×10¯²)
ΔG = 25.22 – 169.8048
ΔG = 8.24 KJ/mol
Thus, the ΔG for the reaction is 8.24 KJ/mol
Learn more about Gibbs free energy:
brainly.com/question/9552459
Answer:
The beginning development of a star is marked by a supernova explosion, with the gases present in the nebula being forced to scatter. As the star shrinks, radiation of the surface increases and create pressure on the outside shell to push it away and forming a planetary nebula or white dwarf. 5.0. 3 votes.
Answer:
21.14
Explanation:
Let the unknown number be y.
Framing the question mathematically,
5.75 + y/2 = -5
y/2 = -5 -5.75
y/2 = -10.57
y = -10.57 × 2
y = 21.14
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>
Answer:
C, Writing
Explanation:
nothing really to explain
Answer:
10 in³
Explanation:
given:
square box = 4 in², length = 16 in
bar diameter = 2 in, length = 16 in
box volume (in solid) = 4 in² * 16 in = 64 in³
bar volume = pi * d² / 4 = 3.14 * 2² / 4 * 16 in = 50.24 in³
Volume of slotted box = 64 - 50 = 10 in³