Question

There are four steps for converting the equation x2 y2 12x 2y – 1 = 0 into standard form by completing the square. Complete the last step. Group the x terms together and the y terms together, and move the constant term to the other side of the equation. X² 12x y² 2y = 1 Determine (b ÷ 2)2 for the x and y terms. (12 ÷ 2)2 = 36 and (2 ÷ 2)2 = 1 Add the values to both sides of the equation. X2 12x 36 y2 2y 1 = 1 36 1 Write each trinomial as a binomial squared, and simplify the right side. (x )2 (y )2 =.

Answer 1

The equation of the circle in squared form is $\rm (x + 6)^2 + (y + 1)^2 = 38$. Then the center of the circle is at (-6, -1).

What is a circle?

It is a locus of a point drawn at an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.

The equation of the circle is given as

$\rm x^{2} + y^2 + 12x +2y - 1 = 0$

This can be written as

$\rm x^{2} + y^2 + 12x +2y = 1$

Add both sides 36 and 1, then

$\rm x^{2} + 12x + 36 + y^2 +2y +1 = 1 + 36 + 1$

Then we know that

$\rm (a+b) ^2 = a^2 + b^2 + 2ab$

Then

$\rm (x + 6)^2 + (y + 1)^2 = 38$

Thus, the center of the circle is at (-6, -1).

More about the circle link is given below.

brainly.com/question/11833983