The correct answer for this question is this one: "D it increases by $1,800,000"
<span>If the federal reserve decreases the reserve rate from 2.5% to 1.25%, this affect the amount of money that would result because of fractional reserve banking from an initial deposit in a bank of $45,000 is that </span><u>it increases by $1,800,000</u>Hope this helps answer your question and have a nice day ahead.
Answer:
30t - 4
Step-by-step explanation:
Remember to follow PEMDAS. First, distribute -6 to all terms within the parenthesis:
2 -6(-5t + 1) = 2 + (-6 * -5t) + (-6 * 1)
2 + (30t) + (-6) = 2 + 30t - 6
Simplify. Combine like terms:
2 + 30t - 6 = 30t + (-6 + 2) = 30t - 4
30t - 4 is your answer.
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Answer:
x2 = -0.600000
x3 = -0.521600
Step-by-step explanation:
Given the formula;
xn+1 = (xn)³-5/10
x2 = (x1)³-5/10
Given x1 = -1
x2 = (-1)³-5/10
x2 = (-1-5)/10
x2 = -6/10
x2 = -0.600000
x3 = (x3)³-5/10
Given x3 = -0.6
x3 = (-0.6)³-5/10
x3 = (-0.216-5)/10
x3 = -5.216/10
x3 = -0.521600
Answer:
The probability that the restaurant can accommodate all the customers who do show up is 0.3564.
Step-by-step explanation:
The information provided are:
- At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53.
- If the probability of a party not showing up is 0.04.
- Assuming independence.
Let <em>X</em> denote the number of parties that showed up.
The random variable X follows a Binomial distribution with parameters <em>n</em> = 53 and <em>p</em> = 0.96.
As there are only 50 sets available, the restaurant can accommodate all the customers who do show up if and only if 50 or less customers showed up.
Compute the probability that the restaurant can accommodate all the customers who do show up as follows:
![P(X\leq 50)=1-P(X>50)\\=1-P(X=51)-P(X=52)-P(X=53)\\=1-[{53\choose 51}(0.96)^{51}(0.04)^{53-51}]-[{53\choose 52}(0.96)^{52}(0.04)^{53-52}]\\-[{53\choose 53}(0.96)^{53}(0.04)^{53-53}]\\=1-0.27492-0.25377-0.11491\\=0.3564](https://tex.z-dn.net/?f=P%28X%5Cleq%2050%29%3D1-P%28X%3E50%29%5C%5C%3D1-P%28X%3D51%29-P%28X%3D52%29-P%28X%3D53%29%5C%5C%3D1-%5B%7B53%5Cchoose%2051%7D%280.96%29%5E%7B51%7D%280.04%29%5E%7B53-51%7D%5D-%5B%7B53%5Cchoose%2052%7D%280.96%29%5E%7B52%7D%280.04%29%5E%7B53-52%7D%5D%5C%5C-%5B%7B53%5Cchoose%2053%7D%280.96%29%5E%7B53%7D%280.04%29%5E%7B53-53%7D%5D%5C%5C%3D1-0.27492-0.25377-0.11491%5C%5C%3D0.3564)
Thus, the probability that the restaurant can accommodate all the customers who do show up is 0.3564.