Given:
A biased dice is thrown 300 times.
Table of probabilities of each score.
To find:
The expected number of times the score will be odd.
Solution:
Odd numbers on the dice are 1, 3, 5. The sum of their probability is
![0.15+0.25+0.3=0.7](https://tex.z-dn.net/?f=0.15%2B0.25%2B0.3%3D0.7)
Even numbers on the dice are 2, 4, 6. The sum of their probability is
![0.05+0.05+0.2=0.3](https://tex.z-dn.net/?f=0.05%2B0.05%2B0.2%3D0.3)
Now, the expected number of times the score will be odd is
![\text{Expected odd number}=300\times \text{Probability of getting an odd number}](https://tex.z-dn.net/?f=%5Ctext%7BExpected%20odd%20number%7D%3D300%5Ctimes%20%5Ctext%7BProbability%20of%20getting%20an%20odd%20number%7D)
![\text{Expected odd number}=300\times 0.7](https://tex.z-dn.net/?f=%5Ctext%7BExpected%20odd%20number%7D%3D300%5Ctimes%200.7)
![\text{Expected odd number}=210](https://tex.z-dn.net/?f=%5Ctext%7BExpected%20odd%20number%7D%3D210)
Therefore, the expected number of times the score will be odd is 210.