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Pepsi [2]
3 years ago
8

A biased dice is thrown.

Mathematics
1 answer:
nexus9112 [7]3 years ago
8 0

Given:

A biased dice is thrown 300 times.

Table of probabilities of each score.

To find:

The expected number of times the score will be odd.

Solution:

Odd numbers on the dice are 1, 3, 5. The sum of their probability is

0.15+0.25+0.3=0.7

Even numbers on the dice are 2, 4, 6. The sum of their probability is

0.05+0.05+0.2=0.3

Now, the expected number of times the score will be odd is

\text{Expected odd number}=300\times \text{Probability of getting an odd number}

\text{Expected odd number}=300\times 0.7

\text{Expected odd number}=210

Therefore, the expected number of times the score will be odd is 210.

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EXERC
eimsori [14]

Answer:551.3212cm³

Step-by-step explanation:

Find the image attached

The volume is made up of a cone, cylinder and a hemisphere

Volume of the shape = Volume of cone + volume of cylinder + volume of hemisphere

Get the volume of the cone;

Volume of a cone Vc = 1/3πr²h

r is the base radius = 3.5cm

Height = 10cm

Vc = 1/3π(3.5)²(6)

Vc = 1/3π(12.25)(6)

Vc = 12.25 * 2π

Vc = 24.5π cm³

Get the volume of the cylinder;

Vcy = πr²h

r = 3.5cm

h = 10cm

Vcy = π(3.5)²(10)

Vcy = π(12.25)(10)

Vcy = π(122.5)

Vcy = 122.5π cm³

Get rhe volume of the hemisphere;

Volume of hemisphere = 2/3 πr³

r = 3.5cm

Vh =  2/3 π(3.5)³

Vh = 2/3π(42.875)

Vh = 28.58π cm³

Volume of the shape = VC + Vcy + Vh

Volume of the shape = 24.5π+122.5π+28.58π

Volume of the shape = 175.58π

<em>Volume of the shape = 551.3212cm³</em>

7 0
3 years ago
a random sample of high school seniors were asked whether they were applying for college. the resulting confidence interval for
Artist 52 [7]

Using the confidence interval, the margin of error is 0.02.

In the given equation we have to find the margin of error.

The resulting confidence interval for the proportion of students applying for college is (0.65,0.69).

Let p = population proportion of students applying for college

P = Sample proportion of students applying for college

ME = margin of error

So the confidence interval

CI = (P-ME, P+ME)

From the given question;

(P-ME, P+ME) = (0.65,0.69)

So lower bound= P-ME = 0.65............................(1)

Upper Bound = P+ME = 0.69............................(2)

Simplifying the Equation 1 and 2

Add equation 1 and 2 we get

2P = 1.34

Divide by 2 on both side we get

P = 0.67

Putting the value of P in the equation 2

P+ME = 0.69

0.67+ME=0.69

Subtract 0.67 on both side we get

ME = 0.02

Hence, the margin of error is 0.02.

To learn more about margin of error link is here

brainly.com/question/10501147

#SPJ4

3 0
1 year ago
Which table represents a linear function?
abruzzese [7]
Yeah the last ^^^^^^^
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Question 37
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It’s 56689 + the power of everything is 25 round it up
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