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pishuonlain [190]
3 years ago
15

What is 129 multiply by 75

Mathematics
2 answers:
qaws [65]3 years ago
8 0

Answer:

9,675

Step-by-step explanation:

lianna [129]3 years ago
4 0

Answer: 9675

Step-by-step explanation: u don’t want to know do u

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Softa [21]
The answer to this question is B!
8 0
3 years ago
Read 2 more answers
A taxi costs 1.65 for the first mile and 0.85 for each additional mile. Which equation could be solved to find the number x of a
diamong [38]
1.65 + 0.85x= $20
           0.85x=$18.35
                 x=21 10/17 
first you write the equation 
then you have to subtract 1.65 from the equation but you also have to subtract it from 20 
then you divide 0.85 from 0.85x and from the 18.35 left over from subtracting 1.65 from 20 
then you should get x=21 10/17 (simplified) but the decimal form is a ongoing fraction so you can just round it up to the nearest hundredth 
5 0
3 years ago
The bill for a meal at a restaurant before tax is $84.00. the sales tax rate is 7% and you want to leave a 20% tip based on the
Strike441 [17]
The pree tax amount count as 100%, then there's the 7% tax and lastly the 20% tip. therefore, one would pay (100+20+7)% of $84.00.
127% of $84.00
(127/100) * $84.00 = $106.68
4 0
3 years ago
"A study conducted at a certain college shows that 56% of the school's graduates find a job in their chosen field within a year
KiRa [710]

Answer:

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they find a job in their chosen field within one year of graduating, or they do not. The probability of a student finding a job in their chosen field within one year of graduating is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

56% of the school's graduates find a job in their chosen field within a year after graduation.

This means that p = 0.56

Find the probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

This is P(X \geq 1) when n = 6.

Either none find a job, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.56)^{0}.(0.44)^{6} = 0.0073

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0073 = 0.9927

99.27% probability that among 6 randomly selected graduates, at least one finds a job in his or her chosen field within a year of graduating.

8 0
3 years ago
Finding it hard. I’d love some help and the answers. Thanks
nevsk [136]

for all of them its base times height

v=bh

1) (8*6/2)*9.5=228

2) (4.5/2)^2 *8= 40.5

3) (3.3* 8.3/2) *5.4= 74.0

4) ((3.2+4.8)/2)* 2.7 *4.4= 47.5

7 0
2 years ago
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