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sergejj [24]
3 years ago
10

45m 34m 74m What is the area

Mathematics
1 answer:
Masja [62]3 years ago
5 0

Answer:

Add all and you will get the answer...........

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The functions f and g are graphed in the same rectangular coordinate system, shown to the right. If g is obtained from f through
german

The first thing we notice is that the function is reflected. So we can start by reflecting it with respect to the x-axis.

We do this by adding a negative sign in the function:

\begin{gathered} f_0(x)=x^2 \\ f_1(x)=-f_0(x)=-x^2 \end{gathered}

Now, we have the function reflected, but in the wrong position. We can track its position by the vertex. It was originally at (0,0) and remains at (0,0) after the reflection.

But the final function have its vertex at (-5,0), so we have to translate the function 5 units to the left. we do this by adding 5 to the x in the function:

f_2(x)=f_1(x+5)=-(x+5)^2

Now, to check if there isn't any dilatation, we can check on other point in the graph to see if it checks out.

In the blue graph, we see the point (-3,-4), so let's input x = -3 and see if it checks out:

f_2(-3)=-(-3+5)^2=-(2)^2=-4

We got y = -4, so it checks out.

Thus, the answer is:

g(x)=-(x+5)^2

3 0
1 year ago
Look at pic broooos so just do it rn
igomit [66]

Answer:

b) 83.2 c) 62.5

7 0
3 years ago
50 POINTS TO WHOEVER ANSWERS THIS NOW!!!! IM TIMED HELP.
NemiM [27]
Part e because I did it and got it right on the test txt me if u need help
3 0
3 years ago
Question 2 Find the slope between the two points: (3, 20) and (5.8)​
GuDViN [60]

Answer:

The slope between the two points: (3, 20) and (5, 8) is -6.​

Step-by-step explanation:

Put the points in the slope formula:

m = (y₂ - y₁)/(x₂ - x₁)

Substitute the values.

m = (8 - 20)/(5 - 3)

Subtract.

m = (-12)/2

Divide.

m = -6

8 0
2 years ago
Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
tangare [24]

Answer:

<h3>The given expression can be written in the form q(x)+\frac{r(x)}{b(x)} as (2x^2-x+3)+\frac{0}{x-3} where  q(x)=2x^2-x+3 , r(x)=0 and b(x)=x-3</h3>

Step-by-step explanation:

Given rational expression is \frac{2x^3-7x^2+6x-9}{x-3}

<h3>To rewrite the given rational expression in the given form  and match their correct expressions:</h3>

Rewrite the given rational expression \frac{2x^3-7x^2+6x-9}{x-3} in the form of q(x)+\frac{r(x)}{b(x)} where q(x) is the quotient, r(x) is the remainder and b(x) is the divisor.

<h3>Now solve the given expression by using Synthetic division, we get</h3>

Since x-3 is a factor for 2x^3-7x^2+6x-9

<h3>Therefore b(x)=x-3</h3>

3_|   2     -7     6     -9

       0      6    -3      9

   ------------------------------------

      2      -1       3      0

  ------------------------------------

Therefore we have quadratic equation 2x^2-x+3=0

<h3>q(x)=2x^2-x+3</h3><h3>Remainder is 0</h3><h3>Therefore r(x)=0</h3>

Therefore we can write in the form as (2x^2-x+3)+\frac{0}{x-3}

It is in the form of q(x)+\frac{r(x)}{b(x)}

<h3>Therefore the given expression can be written in the form q(x)+\frac{r(x)}{b(x)} as (2x^2-x+3)+\frac{0}{x-3} where  q(x)=2x^2-x+3 , r(x)=0 and b(x)=x-3</h3>

3 0
3 years ago
Read 2 more answers
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