Answer: Tristan can pick them out in 6 different ways
Step-by-step explanation: In the waiting room the four magazines all have an equal chance of being picked first and then others would be picked subsequently. If we are to pick magazine A first of all, then the others would be picked as B, C and D, or C, B and D, or D, B and C, and so on.
However, rather than spend so much time counting the different ways we can apply the mathematical method of permutation. Since choosing the first one means we can’t choose it again but others have to be chosen, and all four magazines each has an equal chance of being chosen first, then the number of all possible permutations is given as 4! (four factorial).
The question requires us to chose three out of the four magazines, so we shall apply 3!.
3! = 3 x 2 x 1
3! = 6
Therefore, there are 6 different ways to pick three out of the four magazines
Answer:
It is a function
Step-by-step explanation:
The x has only one y and that makes it a function
Answer:
3/14 chance first draw
Step-by-step explanation:
There are 14 jellybeans in all, you won’t be replacing so the probability will change with each draw.
Probability the 1st draw is red = 3/14.
Probability the 2nd draw is red = (3–1)/(14–1) = 2/13.
Probability the 3rd draw is red = (2–1)/(13–1) = 1/12.
3/14 x 2/13 x 1/12 = 6/2184 = 1/364 is approximately 0.27%, pretty rare.
The algorithm prints out all the possible ways to draw 3 <span>balls in sequence, </span><span> ---Select--- with </span> <span>replacement. It prints</span> <span>lines.</span>
