Ahhh I think that is cheating?
Soz I know the anaswer but I cant tell you have to do by your self to learn you can't always ask for answers :<
SOLUTION
The mean is 4min
standard deviation is 1min
the z score is

where

then we have

The probability the call lasted less than 3 min will be
Therefore, the probability that (z < -1 ) is
[tex]\begin{gathered} Pr(z<-1)=Pr(0
Hence, the percentage of the calls that lasted less than 3 min is 16%
Answer:
you have the table of the 12in the photo
Step-by-step explanation:
Answer:64
Step-by-step explanation:
2×2=4
4×2=8
8×8=64