Answer:
1. 17.27 cm
2. 19.32 cm
3. 24.07°
4. 36.87°
Step-by-step explanation:
1. Determination of the value of x.
Angle θ = 46°
Adjacent = 12 cm
Hypothenus = x
Using cosine ratio, the value of x can be obtained as follow:
Cos θ = Adjacent /Hypothenus
Cos 46 = 12/x
Cross multiply
x × Cos 46 = 12
Divide both side by Cos 46
x = 12/Cos 46
x = 17.27 cm
2. Determination of the value of x.
Angle θ = 42°
Adjacent = x
Hypothenus = 26 cm
Using cosine ratio, the value of x can be obtained as follow:
Cos θ = Adjacent /Hypothenus
Cos 42 = x/26
Cross multiply
x = 26 × Cos 42
x = 19.32 cm
3. Determination of angle θ
Adjacent = 21 cm
Hypothenus = 23 cm
Angle θ =?
Using cosine ratio, the value of θ can be obtained as follow:
Cos θ = Adjacent /Hypothenus
Cos θ = 21/23
Take the inverse of Cos
θ = Cos¯¹(21/23)
θ = 24.07°
4. Determination of angle θ
Adjacent = 12 cm
Hypothenus = 15cm
Angle θ =?
Using cosine ratio, the value of θ can be obtained as follow:
Cos θ = Adjacent /Hypothenus
Cos θ = 12/15
Take the inverse of Cos
θ = Cos¯¹(12/15)
θ = 36.87°
36. You can search it up and look at a times table chat or you can do this 6x5=30+6=36
Answer:
Step-by-step explanation:
2(20 + 22) = 2(42) = 84 total books
D.
Slope is rise over run and in this case it is -15/ 5 so when it is reduced you get -3 as your slope
Answer:
2
Step-by-step explanation:
The height formula given is:
h = -16t^2 + 70
That means the object will be initially (t=0) at the height 70 feet, from where it will be dropped.
If we want to know the time when the object will be at height 6 feet, we just need to use h=6 in the equation, and then calculate the value of t:
6 = -16t^2 + 70
16t^2 = 64
t^2 =4
t = 2 s
So, it will take 2 seconds for the object to be 6 feet above the valley floor.
