Answer:
50 kg
Step-by-step explanation:
Given that:
SMALL HELICOPTERS:
Weight of small helicopters = 3kg
Weight of shipping container = 20kg
LARGE HELICOPTERS:
Weight of large helicopters = 4kg
Weight of shipping container = 10kg
Number of helicopters each shipping container can hold = s ; all of the packed containers will have the same shipping weight
Shipping weight :
(Weight per helicopter * number of helicopter) + weight of shipping container
Shipping weight of Small helicopters :
(3kg * s) + 20
Shipping weight Large helicopters :
(4kg * S) + 10
Shipping weight of Small helicopters = shipping weight of large helicopters
3s + 20 = 4s + 10
20 - 10 = 4s - 3s
10 = s
Hence, member of shipped helicopters = 10
Total shipping weight :
(4 * S) + 10
(4*10) + 10
40 + 10 = 50kg
Answer:

Step-by-step explanation:
1) Use FOIL method: (a + b) (c + d) = ac + ad + bc + bd.

2) Collect like terms.

3) Simplify.

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><u>x</u><u>²</u><u> </u><u>+</u><u> </u><u>9x</u><u> </u><u>+</u><u> </u><u>20</u>.
These are two questions and two answers.
Question 1) Which of the following polar equations is equivalent to the parametric equations below?
<span>
x=t²
y=2t</span>
Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>
Explanation:
1) Polar coordinates ⇒ x = r cosθ and y = r sinθ
2) replace x and y in the parametric equations:
r cosθ = t²
r sinθ = 2t
3) work r sinθ = 2t
r sinθ/2 = t
(r sinθ / 2)² = t²
4) equal both expressions for t²
r cos θ = (r sin θ / 2 )²
5) simplify
r cos θ = r² (sin θ)² / 4
4 = r (sinθ)² / cos θ
r = 4 cosθ / (sinθ)²
r = 4 cot θ csc θ ↔ which is the option A.
Question 2) Which polar equation is equivalent to the parametric equations below?
<span>
x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>
Answer: option B) r = sinθ + 1
Explanation:
1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ
2) replace x and y in the parametric equations:
a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span>
b) r sinθ =sin²(θ)+sin(θ)</span>
3) work both equations
a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1] ⇒ r = sinθ + 1
<span>
b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
Answer: Second Option

Step-by-step explanation:
The exponential growth functions have the following form:

Where a is the main coefficient, b is the base and x is the exponent.
For this type of functions the base b must always be greater than 1. Otherwise it would be an exponential decay function
Among the options given, the only function whose base is greater than 1 is the second option:
