Answer:
the confidence interval for the true weight of the specimen is;
4.1593 ≤ μ ≤ 4.1611
Step-by-step explanation:
We are given;
Standard deviation; σ = 0.001
Sample size; n = 8
Average weight; x¯ = 4.1602
We are given a 99% confidence interval and the z-value at this interval is 2.576
Formula for confidence interval is;
CI = x¯ ± (zσ/√n)
Plugging in the relevant values, we have;
CI = 4.1602 ± (2.576 × 0.001/√8)
CI = 4.1602 ± 0.000911
CI = (4.1602 - 0.000911), (4.1602 + 0.000911)
CI ≈ (4.1593, 4.1611)
Thus, the confidence interval for the true weight will be expressed as;
4.1593 ≤ μ ≤ 4.1611
Where μ represents the true weight
Answer:
578.5$
Step-by-step explanation:
first we calculate 35% of $890
890 * 0.35 = 311.5$
Then we subtract 35% from the original price to obtain the final price
890-311.5=578.5$ <---- final price
2x + 12 = 18
18 - 12 = 6
2x = 6
x = 3
Answer:
4
Step-by-step explanation:
6+2+4+2+2+7+5+6+3+3=40
40/10=4
Therefore the mean is 4
