The number of permutations of the 25 letters taken 2 at a time (with repetitions) is:

The number of permutations of the 9 digits taken 4 at a time (with repetitions) is:

Each permutation of letters can be taken with each permutation of digits, therefore the total number of possible passwords is:
Answer:
1/3
Step-by-step explanation:
reduce 2/6 by dividing by 2
Answer:
10) 9x - 2° = 5x + 54° (corresponding angles are equal)
9x - 5x = 54 + 2
4x = 56
x = 56/4
x = 14°
10y + 6° = 9x - 2° (linear pair)
10y + 6° = 9(14)° - 2°
10y + 6° = 126° - 2°
10y + 6° = 124°
10y = 124° - 6°
10y = 118
y = 118/10
Sorry, i don't know how to do the 11th question
but hope this helps you!
Answer:
You can use Gaussian Elimination.
Double both sides of the first equation and add the second equation.
6x + 4y = 8
5x - 4y = 3
---------------
11x = 11
x = 1
5 - 4y = 3
-4y = -2
y = 1/2
Step-by-step explanation:
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