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tatyana61 [14]
2 years ago
9

A toy was bought for Rs.564 thereby profit 12%. Find the SP of the toy

Mathematics
1 answer:
Kamila [148]2 years ago
3 0

Answer:SPssp=631.68

Step-by-step explanation:

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14x=x^2-15<br><br> find the value of x
hram777 [196]

Answer: x=-1, 15

Step-by-step explanation:

x^2 -14x-15=0\\\\(x-15)(x+1)=0\\\\x=-1, 15

5 0
1 year ago
Perform the indicated operation: (-1 1/2)(-3/2)
LiRa [457]

Answer:

=8 1/4 as a fraction or 8.25 in decimal form.

Step-by-step explanation:

The indicated operation is the product of the two fractions. Multiplication opens the brackets.

(-11/2)×(-3/2)

=(-11×-3)/(2×2)

=33/4

The negative signs before each term cancel out in multiplication and division.

=33/4 =8 1/4= 8.25

Choose 1 answer among the improper fraction, Mixed fraction or the decimal.

6 0
3 years ago
Suppose we lined up all the people in the world (about 6.7 billion people). Assume that each person occupied 12 inches of the li
satela [25.4K]

Answer:

50.757575756‬

Step-by-step explanation:

I put it in calculator and transformed it.

6 0
3 years ago
Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.&lt;b
kherson [118]
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
8 0
3 years ago
Here is a CD rack. One Rack holds 25 CD's. David has 83 CD's. Lin has 6 full racks of CD's. How many racks does David need to ho
Dimas [21]
If David has 83 CD's, and each rack holds 25, then David would need 4 racks. 4 racks will hold up to 100 CD's, where as 3 racks would only hold 75.

I'm not sure what 'Lin' has to do with this equation, but if she has 6 racks full of CD's then in total she has 150 CD's.

Hope this helps! :)
6 0
2 years ago
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