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erik [133]
2 years ago
9

Which expression is equivalent to 8^-3/ 2^-3? a. 4^0 b. 4^-3 c. 1/4^-3 d. 4

Mathematics
1 answer:
Fittoniya [83]2 years ago
3 0

Answer:

  b.  4^-3

Step-by-step explanation:

The expression can be simplified to a number of different levels. Here, it looks like the answer choices want you to simplify it like this:

  \dfrac{8^{-3}}{2^{-3}}=\left(\dfrac{8}{2}\right)^{-3}=\boxed{4^{-3}}

__

In this case, the applicable rule of exponents is ...

  (a/b)^c = (a^c)/(b^c)

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3 years ago
Of the 50 students in an undergraduate statistics class, 60% send email and/or text messages during any given lecture. They have
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Answer:

0.3 or 30%

Step-by-step explanation:

Since no innocent student will ever be caught, the probability that a student sends an email and/or text message during a lecture AND gets caught is given by the product of the probability of a student sending a message (60%) by the probability of the professor catching them (50%) :

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Here is an equilateral triangle. The length of each side is units. A height is drawn. In an equilateral triangle, a line drawn f
Temka [501]

1. Height of the equilateral triangle is: √3 units

2. Area of the equilateral triangle = √3 units²

3. Area = √3/4 x², when each side is x.

<h3>What is an Equilateral Triangle?</h3>

A triangle that has all its three sides equal in length, is referred to as an equilateral triangle.

1. Given the each side measures 2 units, and h is the height, applying the Pythagorean theorem, we would have:

h = √(2² - 1²)

h = √(4 - 1)

h = √3

2. Area of the equilateral triangle = 1/2bh = 1/2(2)(√3)

Area of the equilateral triangle = √3 units²

3. If x is the side length of the equilateral triangle, we would have:

height (h) = √[x² - (x/2)²] = √[x² - x²/4] = √(3x²/4) = √3/2x

Area = 1/2bh = 1/2(x)(√3/2x) = √3/4 x²

Learn more about equilateral triangle on:

brainly.com/question/15294703

#SPJ1

3 0
2 years ago
Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Andre45 [30]

For this case, we must indicate which of the given functions is not defined forx = 0

By definition, we know that:

f (x) = \sqrt {x} has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative when x = 0.

While y = \sqrt {x + 2} if it is defined for x = 0.

f(x)=\sqrt[3]{x}, your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

y = \sqrt [3] {x-2} with x = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x + 2}with x = 0: y = \sqrt [3] {2}in the same way is defined.

Answer:

y = \sqrt {x-2}

Option b


6 0
3 years ago
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