Solve for t. You must write your answer in fully simplified form. −19= 7t

Mathematics

1 answer:

Olenka [21]2 years ago

8 0

Answer: dot know srry

Step-by-step explanation:

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"A student measures the length of a rectangularposter to the nearest centimeter and finds thatthe length is 75 cm. Another stude

anastassius [24]

Answer:

See below

Step-by-step explanation:

The result of the calculation of area ( L x W ) should have no more significant digits than the lowest factor ....in this case 75 has only TWO significant digits...... the naswer should have the same ...two

75 * 50.3 = ~3800 cm^2

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1 year ago

Plzz solve this easy calculus :')

Digiron [165]

Answer:

$\sin \: x - \cos x \: + c$

Step-by-step explanation:

$\int \frac{cos2x}{ \sqrt{1 - sin2x} } dx \\ \\ = \int \frac{ {cos}^{2}x - {sin}^{2}x } { \sqrt{ {sin}^{2}x + {cos}^{2}x - 2sinx \: cosx } } dx \\ \\ = \int \frac{ ({cos}x - {sin}x )({cos}x + {sin}x )} { \sqrt{ {({cos}x - {sin}x )}^{2} } } dx \\ \\ = \int \frac{ ({cos}x - {sin}x )({cos}x + {sin}x )} {{ {({cos}x - {sin}x )} } } dx \\ \\ = \int({cos}x + {sin}x)dx \\ \\ = \int{cos}x \: dx + \int{sin}x \: dx \\ \\ = \sin \: x - \cos x \: + c$

3 0

2 years ago

A rectangular playground is to be fenced off and divided in two by another fence parallel to one side of the playground. Seven h

Arisa [49]

Answer:

Step-by-step explanation:

Suppose the dimensions of the playground are x and y.

The total amount of the fence used is given and it is 780 ft. In terms of x and y this would be 3x+2y=780 (we add 3x because we want it to be cut in the middle). Therefore, y= 780/2-3/2x. Now, the total area (A )to be fenced is

A=x*y= x*(390-3/2x)=-3/2 x^2+390x

Calculating the derivative of A and setting it equals to 0 to find the maximum

A'= -3x+390=0

This yields x=130.

Therefore y=780/2-3/2*130=195

Thus, the maximum area is 130*195=25,350ft^2

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2 years ago

A ball is thrown into the air. The height in feet of the ball can be modeled by the equation h = -16t2 + 20t + 6 where t is the

makkiz [27]

$f(t)=h=-16t^2+20t+6

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